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Nikitich [7]
4 years ago
7

X=5/2-y/4 Solve for x

Mathematics
1 answer:
Bas_tet [7]4 years ago
5 0
X=-1/4y+5/2
You just needed to flip the right side of the equation

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PLEASE HELP ME <br>IM NOT GOOD WITH GRAPHS​
Yuri [45]

Answer:

b

Step-by-step explanation:

3 0
2 years ago
Please help with an explanation!
Artist 52 [7]

Answer:

6 weeks

Step-by-step explanation:

Easier way to solve: If she takes 7 quizzes each week, 7 times something (amount of weeks) equals 42.

7 X <u>6</u> = 42

Solving with algebra: We know that hanna takes six quizzes a week and takes a total of 42 quizzes, therefore the unknown (x) is the amount of weeks she takes the quizzes.

Amount of weeks X amount of tests per weeks = 42 quizzes

<em>x </em>X 7 = 42

42/7 = 6

3 0
2 years ago
Read 2 more answers
I only need 6-10 pleaseeeeswws
Genrish500 [490]
6) 381/100
7) 231/1000
8) -303//25
9) 9/1000
10) -227/50
3 0
3 years ago
For a certain commodity the supply equation is given by S = 2p + 5 At a price of $1, there is a demand for 19 units of the commo
slava [35]

Answer:

The demand equation is: D=-4p+23

Step-by-step explanation:

To get started, we should keep in mind that the market price (p=3) occurs when supply equals demand ,therefore when p=3

S=2(3)+5=11

Thus, when p=3 D=11 and, according to the problem  when p=1 D=19.

We already know two points on the demand curve. Great!

The demand equation is linear, so it has form D=bp+c.

The variable b is the slope of  the demand linear equation . It can be computed through the formula

b=\frac{y2-y1}{x2-x1}.  equation 1

Substituting the two points (3,11) and (1,19) on equation 1.

b=\frac{19-11}{1-3} =\frac{8}{-2}

b=-4

Now we can find the value of  intercept of the demand equation c trough point-slope form y-y1=b(x-x1).

We can use any of the points. Let's take (3,11) and write in point-slope :

y-11=-4(x-3)

y=-4x+11+12

y=-4x+23

Rewrite the linear equation according our variables D and p

D=-4P+23

Finally we found the demand equation !

5 0
4 years ago
A train 100 m long crosses a pole in 5 seconds.Find the speed of the train in kilometre per hour.​
In-s [12.5K]

Answer:

\sf72  km/h

Step-by-step explanation:

Distance covered by the train in crossing the pole = 100 m.

\sf Time \:  taken=5 \:  seconds

\sf \: Speed  \: of \: the \: train =  \frac{Distance }{Time}

\sf =  \frac{100}{5} \:  m/s

\sf \:  = 20 \: m/s

\sf \: =  20 \times \frac{18}{5}  \: km/h

\sf = 72 \: km/h

  • Hence, the speed of the train is 72 km/h
6 0
3 years ago
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