Answer:
Rounding to nearest hundredths gives us r=0.06.
So r is about 6%.
Step-by-step explanation:
So we are given:

where


.


Divide both sides by 1600:

Simplify:

Take the 6th root of both sides:
![\sqrt[6]{\frac{23}{16}}=1+r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D%3D1%2Br)
Subtract 1 on both sides:
![\sqrt[6]{\frac{23}{16}}-1=r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1%3Dr)
So the exact solution is ![r=\sqrt[6]{\frac{23}{16}}-1](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1)
Most likely we are asked to round to a certain place value.
I'm going to put my value for r into my calculator.
r=0.062350864
Rounding to nearest hundredths gives us r=0.06.
Answer:
5f - 45
Step-by-step explanation:
(f-9)(5)
5f-9*5
5f-45
17-10= j i really don't know i just guessed
Answer:
x -2y = -4
Step-by-step explanation:
The slope of the line between points C and D is ...
m = (y2 -y1)/(x2 -x1)
m = (7 -13)/(5 -2) = -6/3 = -2
The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...
y -k = m(x -h) . . . . line with slope m through point (h, k)
y -1 = 1/2(x -(-2))
We can rearrange this to standard form.
2y -2 = x +2 . . . . . multiply by 2
-4 = x -2y . . . . . . . subtract 2y+2
x -2y = -4 . . . . . . standard form equation of the desired line
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