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3 years ago

Greatest common factor of 21,28

Mathematics

2 answers:

ladessa [460]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the GCF, or greatest common factor, of a set of numbers, we should list out each of their factors.

21: 1, 3, 7, 21

28: 1, 2, 4, 7, 12, 28

After listing them out, we can tell that 7 is the greatest number that are in both of these lists.

21: 1, 3, 7, 21

28: 1, 2, 4, 7, 12, 28

So, 7 is the GCF of 21 and 28.

Please mark as Brainliest! :)

Musya8 [376]3 years ago

5 0

The greatest common factor is 7.

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A rectangle is to be drawn with perimeter 64cm. If the length is to be 14cm more than the width, determine the are of the rectan

Vikentia [17]

P = 64 cm

2(( x + 14) + x) = 64

2x + 28 + 2x = 64

4x + 28 = 64

4x = 64 - 28

4x = 36

x = 36/4

x = 4

width = 4

lenight = 18

area = l x b

area = 18 x 4

area = 72

5 0

3 years ago

Can someone help please????

egoroff_w [7]

Y= 80.55% approximately, 80.6% rounded up

Calculations:

The percent (percentage) of a given number p/q can be found, for the most part, without a calculator by a slight change in the notation:

y=the number 29/36 expressed as a percent becomes

y=[29(2.7777777778 approx.)]/[36(2.7777777778 approx.)]

y=0.8055 approx. (Express the decimal numeral as a percent)

y=0.8055(100)

y=

80.55% approx., which is 80.6% rounded up to the nearest tenth percent

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2 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

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3 0

3 years ago

If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will

Tema [17]

Answer:

Hence after 3.98 sec i.e 4 sec Object will hit the ground .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object and it is given by ,

$R=v^2Sin$ (2Ф)/ $g$

Here R= range g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

$R=133^2*Sin(56)/31.36$

$R=14664.84/31.36$

$R=467.62$ fts

Now using Formula for time and range as

$R=VxT$

Vx is horizontal velocity

$Vx=V*cos$ Ф

$Vx=133*cos$ (28)

$Vx=117.43$ ft/sec

So above equation becomes as ,

$467.62=117.43*T$

$T=467.62/117.43$

$T=3.98 sec$

T is approximately equals to 4 sec.

4 0

3 years ago

What is the factored form of n^3+512 (please answer) picture provided

Rama09 [41]

${n}^{3} + 512 \\ = {(n)}^{3} + {(8)}^{3} \\ by \: using \: {a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2}) we \: \: \: get \\ = (n + 8)( {(n)}^{2} - n \times 8 + {(8)}^{2} ) \\ = (n + 8)( {n}^{2} - 8n + 64)$

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0

2 years ago