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Serggg [28]
3 years ago
6

Please help with this ☝️

Mathematics
2 answers:
Tcecarenko [31]3 years ago
7 0
We don't know what kind of help you need, 
because we don't see a question being asked.

'x' in the drawing represents the number 9 .
Perhaps this factoid may be useful somehow.
kipiarov [429]3 years ago
5 0
The two angles (6x+4) and 32 degrees are complementary angles. They add to 90 degrees. The two angles are adjacent and form a right angle. The right angle marker is the square marker. Two adjacent right angles form a straight angle (180 degrees)

Add up the angles and set the sum equal to 90. Then solve for x
(6x+4) + (32) = 90
6x+4 + 32 = 90
6x+36 = 90
6x+36-36 = 90-36 .... subtract 36 from both sides
6x = 54
6x/6 = 54/6 ... divide both sides by 6
x = 9

Since x = 9, this means that
6x+4 = 6*9+4 = 54+4 = 58

So the missing angle is 58 degrees (note how 58+32 = 90)

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Answer:

  • central: XWR, VWU
  • inscribed: VST

Step-by-step explanation:

Point W is the center of the circle. Any angle with W as its vertex is a central angle:

  angles XWR and VWU are central angles

Any angle with its vertex on the circle and rays that intersect the circle is an inscribed angle.

  angle VST is an inscribed angle

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3 years ago
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List the steps to solve this
miskamm [114]

Answer:

Step-by-step explanation:

First, distribute the 2 to the 3z and -6 within the parenthesis.

You know have 6z -12/5 + 6 = 10

Subtract 6 from both sides of the equation

6z -12/5 = 4

Multiply 5 on both sides of the equation

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Add 12 to both sides of the equation

6z = 32

Divide by 6 on both sides of the equation

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I hope that this helps! :)

5 0
3 years ago
A parallelogram has one angle that measures 118°. What are the measures of the other three angles in the parallelogram?
MariettaO [177]

Step-by-step explanation:

<em>Given</em>

<em>We </em><em>know </em><em>that </em><em>in </em><em>a </em><em>parallelogram </em><em>opposite </em><em>angles </em><em>are </em><em>equal</em><em>. </em><em>So </em>

<em>1st </em><em>and </em><em>3rd </em><em>angles </em><em>=</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em>

<em>Let </em><em>2nd </em><em>and </em><em>4th </em><em>angles </em><em>=</em><em> </em><em>x</em>

<em>Now</em>

<em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>(</em><em> </em><em>Being </em><em>sum </em><em>of </em><em>angles </em><em>of </em><em>parallelogram</em><em>) </em>

<em>2</em><em>3</em><em>6</em><em>°</em><em> </em><em>+</em><em> </em><em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em>

<em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>2</em><em>3</em><em>6</em><em>°</em>

<em>2x </em><em>=</em><em> </em><em>1</em><em>2</em><em>4</em><em>°</em>

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<em>Now </em><em>the </em><em>measure </em><em>of </em><em>other </em><em>all </em><em>angles </em>

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user100 [1]

Answer:

I hope you got it and it helped you

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