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3 years ago

Round 637.892 to whole number

Mathematics

2 answers:

Vlada [557]3 years ago

8 0

Answer:

the answer is 638!!!!!!!!!!!!!

Stels [109]3 years ago

4 0

Answer:

638

Step-by-step explanation:

its 638, not 639 because its above 638.5

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Will help you with something if u help me plsss

Black_prince [1.1K]

Answer:

21900

Step-by-step explanation:

Find 8% of 7500 (600) and multiply it by 24 (amount of months) then add that to 7500

8 0

3 years ago

The low temperatures for a week in Edmonton, Alberta are -15 C, -12 C, -10 C, -12 C, -18 C, -20 C, and -25 C. What is the mean l

MakcuM [25]

-15.7

Step-by-step explanation:

-15

-12

-10

-12

-18

-20

-25

-------

-110

7 divide by -110=-15.7

7 0

4 years ago

Select all correct answers

Luden [163]

<h2>Answer = </h2><h2> $= \frac{1}{y {}^{5} x {}^{2} }$ </h2>

Step-by-step explanation:

Greetings !

simplify for variable y first

apply exponent rule

$a {}^{b} .a {}^{c} = a {}^{b +c \\ } \\ y {}^{ - 8}y {}^{5} = y {}^{ - 8 + 3}$

Add/subtract the numbers -8+3=5

$= y {}^{5}$

Apply exponent rule

$a {}^{ - b} = \frac{1}{a {}^{b} }$

Thus,

$y {}^{ - 5} = \frac{1}{y {}^{5} }$

secondly, simplify for the variable x

Apply exponent rule as we made on y

$x {}^{ - 2}$

$x {}^{ - 2} = \frac{1}{x {}^{2} }$

multiply bot the values we get

Hope it helps!

5 0

2 years ago

HELP PLEASE !!!!!!!!!!!!!!!

nadya68 [22]

Answer:

x=30

Step-by-step explanation:

if 30 x 4 = 120 amd 2 = 30 = 60 then 60+120=180

6 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers