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dedylja [7]
3 years ago
14

(-1/3,4) is the solution set of?

Mathematics
1 answer:
Nostrana [21]3 years ago
5 0
Solution set of what ?
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Solve this quadratic equation by completing the square.<br><br> x^2+10x=7
bogdanovich [222]
Ok, so the quadratic coefient is 1, so great

take 1/2 of the linear coefient and square it
10/2=5, (5)^2=25
add that to both sides
x^2+10x+25=7+25
factor perfect square trionomial
(x+5)^2=32
squaer root both sides
x+5=+/-4√2
minus 5
x=-5+/-4√2


x=-5+4√2 and -5-4√2
3 0
3 years ago
Four expressions equivalent to 4(3/5)
kondaur [170]
1. 12/5
2. 24/10
3. 48/20
4. 96/40

5 0
4 years ago
Read 2 more answers
2,451 people came to watch the Easter parade. 745 of those people were adults. How many children came to the parade?​
8_murik_8 [283]

Answer:f

Step-by-step explanation:d

8 0
3 years ago
n a word processing document answer the following question. How could you use Descartes' Rule and the Fundamental Theorem of Alg
notka56 [123]
<span>I will discuss polynomials. A polynomial can be classified according to the number of expressions that it has in a given equation. A monomial has only one expression having a coefficient (number) and a variable (letter). A binomial has two expressions, same as the definition of the monomial. And a trinomial has three expressions, same as the definition of a monomial. We can determine the degree of a polynomial by looking at the exponents of the given polynomial. If an expression has two variables with different exponents, you can add their exponent to determine their degree.

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3 0
3 years ago
Which out of the 2 choices is correct ?
tiny-mole [99]

Answer:

sinB is correct

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB = \frac{adjacent}{hypotenuse} = \frac{6}{3\sqrt{5} } = \frac{2}{\sqrt{5} } and

\frac{2}{\sqrt{5} } × \frac{\sqrt{5} }{\sqrt{5} } = \frac{2\sqrt{5} }{5} ≠ \frac{\sqrt{5} }{5}

--------------------------------------------------------------------------------

sinB = \frac{opposite}{hypotenuse} = \frac{3}{3\sqrt{5} } = \frac{1}{\sqrt{5} } and

\frac{1}{\sqrt{5} } × \frac{\sqrt{5} }{\sqrt{5} } = \frac{\sqrt{5} }{5}

7 0
4 years ago
Read 2 more answers
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