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goblinko [34]
3 years ago
6

A rectangular table top measures 7/9 of a meter long by 5/4 of a meter wide. What is its area?

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0

Answer:

35/36 sq meters

Step-by-step explanation:

7/9 x 5/4 = 35/36 sq meters

melamori03 [73]3 years ago
4 0

Answer:

35/36 Sq meters

Step-by-step explanation:

you have to multiply 7/9 x 5/4 = 35/36 Sq meters

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b + c = 1.5b - 1.5c
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The speed of the current is 1.5 mph so
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Is the function g(x)=9<br> x+1 linear or nonlinear?
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Evaluate 48×15^2-5^2×2×24 by using factorisation and algebraic identities.
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Step-by-step explanation:

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3 years ago
At leslie's school the ratio of boys and girls is 11 to 12 at marks school the ratio of boys girls is 41 to 48 if both schools h
Softa [21]

Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

Step-by-step explanation:

Here are the options:

A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.

B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:

= 11/(11 + 12) = 11/23 = 0.4783

At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:

= 41 / (41 + 48) = 41/85= 0.4824

Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

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3 years ago
Power (denoted by PPP) can be defined as a function of work (denoted by WWW) and time (denoted by ttt) using this formula: P=\df
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Answer:

\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

Step-by-step explanation:

Power (denoted by P) can be defined as a function of work (denoted by W) and time (denoted by t) using this formula:

P=\dfrac{W}{t}

Unit of Work = \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2}

Unit for Time = s

Therefore, the Unit of Power

=$Unit for W \times \dfrac{1}{\text{Unit for time}}

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An appropriate unit for power is: \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

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