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Ede4ka [16]
3 years ago
11

find the slope and y intercept for the following equation by writing it in the form y=mx+b -8x+y=5 someone help please

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

slope = 8, y- intercept = 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Given

- 8x + y = 5 ( add 8x to both sides )

y = 8x + 5 ← in slope- intercept form

with slope m = 8 and y- intercept c = 5

Aleksandr-060686 [28]3 years ago
3 0

Answer:

y = 8x + 5

Step-by-step explanation:

-y= -8x - 5

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What is z? -0.25z = -1.25
lora16 [44]
It is (positive) five. divide -1.25 by -0.25.
3 0
3 years ago
Read 2 more answers
What is y=2x+4 and 3x+y=9 substitution method
soldier1979 [14.2K]
You plug in 2x + 4 into the y for the other equation (3x +y ) and solve for it
8 0
3 years ago
The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the
12345 [234]

Answer:

4x^2-21x-2

Step-by-step explanation:

Given that:

Difference of two trinomials is x^2 - 10x + 2

One of the two trinomials is  3x^2 - 11x - 4

To find:

The other trinomial = ?

Four options are:

2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2

Solution:

Let the two trinomials be A and B.

Given A - B = x^2 - 10x + 2

B = 3x^2 - 11x - 4

We have to find the other trinomial A.

A - B = x^2 - 10x + 2

A - (3x^2 - 11x - 4) = x^2 - 10x + 2

\Rightarrow A = x^2 - 10x + 2 + (3x^2 - 11x - 4)

\Rightarrow A = 4x^2-21x-2

So, the correct answer is 4x^2-21x-2.

3 0
3 years ago
Plz i need help and plz explain
Montano1993 [528]

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

x² - x - 12 ≠ 0

x² - 4x + 3x - 12 ≠ 0

x (x - 4) + 3 (x - 4) ≠ 0

(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

3 0
3 years ago
11. Write the equation in slope intercept form that has a slope of -23 and passes through the point (-1, 2).
insens350 [35]
11. y = -23x - 21

You can get this by starting with y = mx + b (slope intercept form). Then put in all the knowns and solve for the b. 

2 = -23(-1) + b
2 = 23 + b
-21 = b

Then add that to the end of the equation with m = -23

12. -5

The y-intercept of an equation is always the number added on at the end of an equation. It is also the number with no x attached to it. 

13. 8x^9y^6

When you use the law of exponents, you need to make sure the exponent goes to each individual term. When we cube the 2, it becomes 8. When you cube x^3, you get x^3*x^3*x^3 or x^9. And with y^2 you get y^6 
7 0
3 years ago
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