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Mathematics

2 answers:

klasskru [66]3 years ago

5 0

Answer: >

Step-by-step explanation: the square root of 17 is going to be larger than the square root of 11. since you add 3 to both equations, that is all you have to worry about.

Helen [10]3 years ago

4 0

Answer:

Step-by-step explanation:

sqrt{17} > sqrt{11}

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3y+2x-4+5x+7<br> Simplify

Vinil7 [7]

Answer:

3y+7x+3

Step-by-step explanation:

3y+2x+5x-4+

=3y+7x+3

4 0

3 years ago

What is 12.38 expanded in form

Lana71 [14]

12.38 in expanded form is write like:-

10 + 2 + .3 + .08 = 12.38

To write a number in expanded form just means to write the number in a layout and when you add it up it will become the number you needed to write in expanded form.

So, 12.38 written in expanded form is:- 10 + 2 + .3 + 0.8

Hope i helped

3 0

4 years ago

Read 2 more answers

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$