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3 years ago

Which property justifies this statement?

Mathematics

1 answer:

professor190 [17]3 years ago

8 0

Answer:

it has to be the division property

Step-by-step explanation:

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Please Explain How To Solve This

atroni [7]

Answer:

Step-by-step explanation:

domain is always the x-values, the first number of an ordered pair. and yes, the x and y values increase at a constant rate.

problem #1:

x / y

-2 -1

-1 -3

0 -5

1 -7

problem #4:

(5, 1) (6, 2) (7, -3) (8, 4) (9, 5)

hope this all helped ;)

mark me brainliest :D

4 0

3 years ago

Read 2 more answers

You are debating about whether to buy a new computer for $800.00 or a refurbished computer with the same equipment for $640.00.

liraira [26]

APR refers to annual interest rate i e 4.5%

Difference:-

800-640
160$

Now

Interest:-

160(0.045)
7.20$

Total savings:-

160+7.20
167.20$

Remember the code:-

Question's calculations mostly given in its options

4 0

2 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .