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Maru [420]
3 years ago
13

What is the largest prime factor of 200

Mathematics
2 answers:
marissa [1.9K]3 years ago
7 0
5 I believe.

2 x 2 x 2 x 5 x 5

Hope this helps!
STSN
likoan [24]3 years ago
3 0
Why don’t you do the work yourself? Huh?
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The shape of the clock is a regular dodecagon with a radius of 14cm. Centered on the clock's face is a green circle of radius 9c
faust18 [17]
The area of a dodecagon is 1/2aP
where:
a-apothem
P-perimeter

In the figure you will draw a point to any side and make a line perpendicular from a center to that side. Then if u think u can see that with only one draw of a hypotenuse can form a triangle. Then after drawing the hypotenuse which has 2 triangles, make the top angle of 1 triangle there are 30 degrees. On the down part is perpendicular and the left or the right is the 60 degrees. After that using special right triangles like the 30, 60, 90,. Then at the base of the one it bisected dived them by 2 for the 2 triangle's base. After that solve using it since the radius is 14. The apothem is 14(sqrt of 3). So after solving them the perimeter of each dodecagon is 12 sided so 14x12 is 168

A=1/2aP
A=1/2(14)(sqrt of 3)(168)
A=1176(sqrt of 3)

Thats the area of the dodecagon now the circle

A=(pi)r^2
A=(pi)(9)^2
A=81pi

Therefore the color purple is greater than the color green
8 0
3 years ago
Sally’s age is two times Sydney’s age. The sum of their age is 27. What is Sydney’s age?
masya89 [10]

Answer:

9

Step-by-step explanation:

18+9=27, answer=9......

7 0
3 years ago
Read 2 more answers
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Studentka2010 [4]
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6 0
3 years ago
Consider it this cone with a diameter of 19 cm use the drop-down menus to describe the con measurements
MAVERICK [17]

Answer:

1) Radius of the cone = 9.5 cm

2) BA = 90.25 π cm²

3) SA = 384.7 π cm²

Step-by-step explanation:

1) Radius of the cone = 9.5 cm

2) Base Area of the cone = \pi r^2

BA = (π)(9.5)²

BA = 90.25 π cm²

3) Surface Area of Cone = \pi r(r+\sqrt{h^2+r^2)}

SA = π(9.5)(9.5 + √(29.5)²+(9.5)²)

SA = 9.5π(9.5 + 31)

SA = 9.5π(40.5)

SA = 384.7 π cm²

3 0
4 years ago
The maths question for algebra is
ankoles [38]

Step-by-step explanation:

Let (2n +1) be the larger odd number by definition, where n can be any real integer. Then (2n - 1) is the smaller consecutive odd number.

The product of the 2 odd numbers is (2n + 1)(2n - 1) = 4n^2 - 1 = 2(2n^2) - 1. Since n^2 must be an integer, 2(2n^2) - 1 is odd. (Shown)

4 0
3 years ago
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