1. find our slope: y2 - y1/ x2- x 1
-9 + 4= -5
2 - 2 = 0
m = 0
2. now we need to use our point-slope form to find our y intercept
point-slope form: y - y1 = m(x - x1)
y + 4 = 0(x - 2)
distribute:
y + 4 = 0x
3. get y by itself
y + 4 - 4 = y
0x - 4 = 0x - 4
4. write in slope-intercept form:
y = 0x - 4
OR
y = -4
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer:
<h2>x = 10√3</h2>
<u>Step-by-step explanation:</u>
cos 45° = base / hypotenuse
1/√2 = base / 15√2
15√2 = base√2
Base, = 15
sin 60° = perpendicular / hypotenuse
hypotenuse = x
√3/2 = 15 / x
x √3 = 30
x = 30 / √3
x = 10√3
Answer:
B=112 degrees A=68 degrees and C=68 degrees
Step-by-step explanation:
the opposite angle of the 112-degree angle is the angle on the top left of the page, this means both of the angles are the same. You can then tell that that angle is the same as the one across from it because it shows on the page. You can then figure out the opposite angle which is B so that means angle B is equal to 112 degrees. To figure out angle A you can just do 180 minus the angle B which is 112 degrees. You now know angle A which is 68 degrees, now to find the angle C you just have to notise that angle C is the opposite angle of angle A. This means that algle C is also 68 degrees.
The triangle pay $32 more for that day than it paid per day during the first period of time.
Step-by-step explanation:
The given is,
Triangle Construction pays Square Insurance $5,980
To insure a construction site for 92 days
To extend the insurance beyond the 92 days costs $97 per day
Triangle extends the insurance by 1 day
Step:1
Insurance per day from the 92 days period,
Where, Total insurance for 92 days = $ 5,980
Period = 92 days
From the values, equation becomes,
= $ 65 per day
Step:2
Insurance per day after the 92 days,
= $ 97
Amount Pay for that day than it paid per day during the first period of time,
= $32
Result:
The triangle pay $32 more for that day than it paid per day during the first period of time, if the Triangle Construction pays Square Insurance $5,980
to insure a construction site for 92 days and to extend the insurance beyond the 92 days costs $97 per day.
