Yes because of ASA
Angel MLX =angel JLM
JLM =90
They share a side (included ) so it is ASA
Area of the rectangle is given as = 16 square inches
We know
Length * width = Area
Then
Width = Area/Length
Now
Perimeter = 2 (Length + Width)
Perimeter = 2[ {Length + (Area/Length)}]
Perimeter = 2[Length + (16/Length)]
When d(Perimeter)/d(length) = 0,
Then
2[Length + (16/Length)] = 0
Length + (16/Length) = 0
Length^2 + 16 = 0
(Length)^2 = -(4)^2
Then
Length = 4 inches
Now
Width = Area/Length
= 16/4
= 4 inches.
Actually none of the answers is correct - it's neither 30,900 nor 40,000.
30,944 rounded to the nearest ten thousand will give us 30,000. It's because 30,944 is closer to 30,000 than to 40,000.
Solve by using <span>Quadratic Formula
</span>
In this case,
![a=16](https://tex.z-dn.net/?f=a%3D16)
<span>,</span>
![b=-32](https://tex.z-dn.net/?f=%20b%3D-32)
<span> and </span>
![c=25{y}^{2}-159](https://tex.z-dn.net/?f=c%3D25%7By%7D%5E%7B2%7D-159)
<span>
</span>
![x= \dfrac{32+ \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} ,}](https://tex.z-dn.net/?f=x%3D%20%5Cdfrac%7B32%2B%20%5Csqrt%7B%2832%29%5E2-4%2A16%2825y%5E2-159%29%7D%20%7D%7B2%2A16%7D%20%2C%7D)
<span>
</span>
<span>
</span>
![x=1+ \dfrac{5i \sqrt{y^2-7} }{4} ,1- \dfrac{5i \sqrt{y^2-7} }{4}](https://tex.z-dn.net/?f=x%3D1%2B%20%5Cdfrac%7B5i%20%5Csqrt%7By%5E2-7%7D%20%7D%7B4%7D%20%2C1-%20%5Cdfrac%7B5i%20%5Csqrt%7By%5E2-7%7D%20%7D%7B4%7D%20)
<span>
</span>