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Airida [17]
3 years ago
10

Heeeeellllllpppppppp PLZ FAST

Mathematics
1 answer:
grin007 [14]3 years ago
6 0
The answer to this question is b
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Step-by-step explanation:

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madreJ [45]

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x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

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<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

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             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

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Name a pair of lines that apear to be parallel
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Hope it helps !!!</span>
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