The area of the parallelogram with a height of 13cm and base 20cm is 260cm².
<h3>
How to find area of a parallelogram?</h3>
A parallelogram is simply a quadrilateral with two pairs of parallel sides.
The area of a parallelogram is expressed as;
A = base × height
Given the data in the diagram;
- Height of the parallelogram = 13cm
- Base of the parallelogram = 20cm
- Area of the parallelogram = ?
Plug the given values into the equation above and solve for A.
A = base × height
A = 20cm × 13cm
A = 260cm²
The area of the parallelogram with a height of 13cm and base 20cm is 260cm².
Learn more about parallelogram here: brainly.com/question/1563728
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Answer:
Step-by-step explanation:
The genral form of a complex number in rectangular plane is expressed as z = x+iy
In polar coordinate, z =rcos ∅+irsin∅ where;
r is the modulus = √x²+y²
∅ is teh argument = arctan y/x
Given thr complex number z = 6+6√(3)i
r = √6²+(6√3)²
r = √36+108
r = √144
r = 12
∅ = arctan 6√3/6
∅ = arctan √3
∅ = 60°
In polar form, z = 12(cos60°+isin60°)
z = 12(cosπ/3+isinπ/3)
To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)
z^1/4 = 12^1/4(cosπ/12+isinπ/12)
When n = 1;
z1 = 12^1/4(cosπ/3+isinn/3)
z1 = 12^1/4cis(π/3)
when n = 2;
z2 = 12^1/4(cos2π/3+isin2π/3)
z2 = 12^1/4cis(2π/3)
when n = 3;
z2 = 12^1/4(cosπ+isinπ)
z2 = 12^1/4cis(π)
when n = 4;
z2 = 12^1/4(cos4π/3+isin4π/3)
z2 = 12^1/4cis(4π/3)
Answer:
$172,984.44
Step-by-step explanation:
We can use the formula
to compute the final amount
Here P is the principal amount, the original deposit = $25,000
r is the annual interest rate = 6.5% = 0.065 in decimal
n is the number of times the compounding takes place. Here it is quarterly so it is 4 times a year
t is the number of time periods ie 30 years
A is the accrued amount ie principal + interest
Computing different components,



Therefore

Step 
In the right triangle ADB
<u>Find the length of the segment AB</u>
Applying the Pythagorean Theorem

we have

substitute the values



Step 
In the right triangle ADB
<u>Find the cosine of the angle BAD</u>
we know that

Step 
In the right triangle ABC
<u>Find the length of the segment AC</u>
we know that




solve for AC

Step 
<u>Find the length of the segment DC</u>
we know that

we have


substitute the values


Step 
<u>Find the length of the segment BC</u>
In the right triangle BDC
Applying the Pythagorean Theorem

we have

substitute the values



therefore
<u>the answer is</u>

23.5 feet
22.5 times 5.5= 129.25
129.25 divided by 7.5 = 23.5