Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
Answer: A. The sequence is arithmetic and has a common difference of 10.
Step-by-step explanation:
-8 +10=2
2+10= 12
12+10 =22
The all have a common difference of 10.
Given:
A line passes through two points are (2,11) and (-8,-19).
To find:
The equation of the line.
Solution:
The line passes through two points are (2,11) and (-8,-19). So, the equation of line is
Using distributive property, we get
Adding 11 on both sides, we get
Therefore, the equation of line is . So, the missing values are 3 and 5 respectively.
6 weeks until she reaches 60 kilo
Answer:
totoy bilat yan po ung sagit
Step-by-step explanation:
mo maitim