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3 years ago

Please help! 10 points up

Mathematics

2 answers:

Oksanka [162]3 years ago

3 0

$sine=\dfrac{opposite\ leg}{hypotenuse}\to\boxed{B}$

Other:

$\dfrac{hypotenuse}{opposite\ leg}=cosecant\\\\\dfrac{opposite\ leg}{adjacent\ leg}=tangent\\\\\dfrac{adjacent\ leg}{hypotenuse}=cosine$

Natasha_Volkova [10]3 years ago

3 0

the opposite leg/hypotenuse=sine of an angle in a right triangle

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