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3 years ago

5

The first two rituals to appear in christianity

1 answer:

Wewaii [24]3 years ago

7 0

Answer:Depending on the specific denomination of Christianity, practices may include baptism, Eucharist (Holy Communion or the Lord's Supper), prayer (including the Lord's Prayer), confession, confirmation, burial rites, marriage rites and the religious education of children

Step-by-step explanation:please mark as brainliest

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Ms. Zab gave a group of 5 students a total of 18.75 liters of water for a science experiment. If each student in the group used

wlad13 [49]

Answer: The quantity of the water received by each student = 3.75 liters.

Step-by-step explanation:

Given: Total water = 18.75 liters

Total students =5

If each student in the group used the same amount of water for their experiment, then the quantity of the water received by each student = $\dfrac{\text{Total quantity}}{\text{Total students}}$

$=\dfrac{18.75}{5}\\\\=3.75\ liters$

The quantity of the water received by each student = 3.75 liters.

4 0

3 years ago

gary is making a cakerecipe that requires 3/4 cup of flour. But gary wants to make the cake half of the size that the recipe cal

vfiekz [6]

Answer:

0.375 cups or 3/8

Step-by-step explanation:

divide 3/4, or 0.75 by 2!

8 0

3 years ago

35 points<br> What is an approximate average rate of change of the graph from x = 8 to x = 13

Ghella [55]

Rate of change is -2 because you can do rise over run to find the constant rate of change, and since you are going down you have a negative slope.

4 0

3 years ago

Andre45 [30]

Answer:

I think the answer is c

Step-by-step explanation:

Because it says at most? am I right

8 0

3 years ago

Read 2 more answers

You have 200 dice in a bag. One of the dice has a six on all sides so it will land on a six every time you roll it. The other 19

LiRa [457]

Answer:

Step-by-step explanation:

There are 200 dice out of which 199 are fair

Prob for 6 in one special die = 1 and

Prob for 6 in other die = 1/6

A1- drawing special die and A2 = drawing any other die

A1 and A2 are mutually exclusive and exhaustive

P(A1) = 1/200 and P(A2) = 199/200

B = getting 6

i) Required probability

= P(A1/B) = $\frac{P(A1B)}{P(A1B)+P(A2B)} \\$

P(A1B) = $\frac{1}{200} *1 = \frac{1}{200}$

P(A2B) = $\frac{199}{200}*\frac{1}{6}=\frac{199}{1200}$

P(B) = $\frac{205}{1200} =\frac{41}{240}$

P(A1/B) = $\frac{1/200}{41/240} =\frac{7}{205}$

P(A2/B) = $\frac{199/1200}{41/240} =\frac{199}{205}$

4 0

3 years ago