Question

Question 4 Unsaved What is the remainder when the polynomial 6x2+11x−3 is divided by 2x−1?

Answer 1

To divide the polynomial $6x^2+11x-3$ by the polynomial $2x-1,$ you have to do such steps:

1 step. Multiply the polynomial $2x-1$ by $3x$. You get the polynomial $6x^2-3x.$

2 step. Subtract the polynomial  $6x^2-3x$ fro mthe polynomial $6x^2+11x-3:$

$6x^2+11x-3-(6x^2-3x)=6x^2+11x-3-6x^2+3x=14x-3.$

Step 3. Multiply the polynomial $2x-1$ by $7$ to get the polynomial $14x-7.$

Step 4. Subtract the polynomial  $14x-7$ from the polynomial $14x-3:$

$14x-3-(14x-7)=14x-3-14x+7=4.$

Step 5. Write the division result:

$6x^2+11x-3=(2x-1)(3x+7)+4.$

Here the quotient is the polynomial $3x+7$ and the remainder is the polynomial $4.$

Answer: the remainder is 4.

Answer 2

Answer:

-1

Step-by-step explanation:

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