1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erica [24]
2 years ago
14

A screening test for a disease shows a positive result in 91% of all cases when the disease is actually present and in 7% of all

cases when it is not. Assume that the prevalence of the disease is 1 in 650. If the test is administered to a randomly chosen individual, what is the probability that the result is positive
Mathematics
1 answer:
Jobisdone [24]2 years ago
4 0

Answer:

0.0713 = 7.13% probability that the result is positive.

Step-by-step explanation:

Probability of a positive test:

91% of 1/650(has the disease).

7% of 1 - 1/650 = 649/650(does not have the disease). So

p = 0.91\frac{1}{650} + 0.07\frac{649}{650} = \frac{0.91 + 0.07*649}{650} = 0.0713

0.0713 = 7.13% probability that the result is positive.

You might be interested in
What is the GCF of 48m5n and 81m2n2?
Lady bird [3.3K]
To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.

Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.

Combining the three, we have the overall GCF = 3m2n
7 0
3 years ago
Read 2 more answers
i believe that it’s a but i don’t want to get it wrong can someone help me (no wrong answers pleaseee)
VARVARA [1.3K]

Answer:

B

Step-by-step explanation:

For the divisor on the left of the division symbol, the -3 symbolizes that the -3 is a root. This means that when we plug -3 into our divisor, the answer is 0. Therefore, as x+3=0 when x=-3, the divisor is x+3.

Next, for the dividend, we can start on the left with no x multiplied to it and then add one degree of x for each value to the left. This results in

6 + -4 * x¹ + 4 * x² + 2 *x³

= 2x³ +4x² -4x+6

6 0
2 years ago
Describe the Reagan doctrine concerning the fight against communism then provide two examples of how the doctrine looked in acti
dimulka [17.4K]

Answer:

It was President Reagan’s support for anti-communist revolutions. It was used as an attempt to end the Cold War (geopolitical tension after world war ll)

8 0
3 years ago
Please help me plot this
Thepotemich [5.8K]

Answer:

D' (-4,-2)

E' (-1,2)

F' (2,-4)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can someone help me with these
vampirchik [111]

Answer: x-intercept is -9

Step-by-step explanation: To find the x intercept y is 0 and to find the y intercept x is 0. 18 divided by -2 is -9, which is the answer

3 0
3 years ago
Other questions:
  • The floral shop marks up their arrangements 31% on cost. If the floral arrangement costs $150, what would the selling price be?
    15·2 answers
  • Can someone nice enough help me ASAP this is 5th Grade Math!
    6·2 answers
  • 8x-y+3x what is the answer for that
    10·1 answer
  • What is the volume of this cone?
    14·1 answer
  • What is the improper fraction as a mixed number : 7/2
    9·1 answer
  • What i this pls help me out
    12·2 answers
  • How many solutions does this have
    6·2 answers
  • Pls help me i only have a few mins to answer this question, thank you!
    15·1 answer
  • Translate the following words into an ALGEBRAIC EXPRESSION:
    10·1 answer
  • The volume of a crate with length of x feet, width of 8 - x feet, and a height of x - 3 feet is given by V(x)=x(8−x)(x−3) find t
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!