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erma4kov [3.2K]

3 years ago

5

11 students went on a trip to New York City. 3 of them visited the Statue of Liberty. What fraction of the students visited the

Statue of Liberty?

2 answers:

neonofarm [45]3 years ago

7 0

3/11 went to visit the statue of liberty

Ne4ueva [31]3 years ago

5 0

so since only 3 out of 11 went to visit then it is simple

since just 3 went and there were 11

3/11 of the students went

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The water was pumped out of a backyard pond. What is the domain of this graph?

Nata [24]

Answer:

The domain of this graph is

d. real numbers from 0 to 7

Step-by-step explanation:

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2 years ago

A stone is an Old English unit of weight and equal to 14 slug. How many kilograms are there in 6 stones? (1 slug = 14.59 kg) Ans

Ber [7]

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1225.56 kg

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8 0

2 years ago

How it came to this

ryzh [129]

You were really close :D
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4 0

2 years ago

Drag each title to the correct box. Not all tiles will be used

mestny [16]

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

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5 0

2 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

1 year ago

Read 2 more answers