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ra1l [238]
3 years ago
5

COCl2(g) CO(g) + Cl2(g) Keq = 8.1 x 10-4. What is true for this system?

Mathematics
1 answer:
Savatey [412]3 years ago
5 0
Ke is the products over the reactants. Since Ka is sosmall, it must
mean that COCl2 has a huge concentration by comparrison
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Solve for x<br> a 2.2<br> b 5.4<br> c 6.5<br> d 7.2
Reika [66]

Answer:

D

Step-by-step explanation:

Given that the segment is an angle bisector then the ratio of sides and base are equal, that is

\frac{10}{4} = \frac{18}{x} ( cross- multiply )

10x = 72 ( divide both sides by 10 )

x = 7.2 → D

8 0
3 years ago
Write an expression for the sequence of operations described below.
Natalka [10]

u( t - 2s)

double s is expressed as 2s

subtract this result from t gives t - 2s

multiply this result by u gives u × (t - 2s) = u( t - 2s)


4 0
3 years ago
Answer the right question
SVETLANKA909090 [29]

Answer:

ok

Step-by-step explanation:

3 0
3 years ago
Assume the following triangles are similar. Find the scale factor and the lengths of the missing sides.
Elanso [62]

Answer:

If two figures are similar, then the correspondent sides are related by a constant factor.

For example, if the base of one side of one of the figures has a length L, then the correspondent side of the other figure has a length k*L where k is the scale factor.

Let's start with the two left triangles.

In the smaller one the base is 5, and the base of the other triangle is 15.

Then we will have:

15 = k*5

15/5 = k = 3

The scale factor is 3.

Then we will have that:

a = scale factor times the correspondent side in the smaller triangle:

a = k*3 = 3*3 = 9

a = 9

For the other two triangles, the base of the smaller triangle is 12, while the base of the larger triangle is 20.

Then we will have the relation:

12*k = 20

k = (20/12) = 10/6 = 5/3

The scale factor is 5/3

This means that the unknown side b is given by:

b*(5/3) = 15

b = (3/5)*15 = 3*3 = 9

b = 9.

5 0
3 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
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