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Elena L [17]
4 years ago
12

P= 2(i+w) what is the solution for I?

Mathematics
1 answer:
Dafna11 [192]4 years ago
8 0

First you had to switch sides of equation.

2(i+w)=p

Then you divide by two from both sides of equation form.

\frac{2(i+w)}{2}= \frac{p}{2}

Simplify.

i+w=\frac{p}{2}

Next, subtract by i from both sides of equation form.

i+w-i=\frac{p}{2}-i

Finally, simplify by equation.

w=\frac{p}{2}-i

Final answer: \boxed{w=p/2-i}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

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How many solutions are there to the equation below ? 8x+47 =8 (x+5)
Rainbow [258]

First, distribute the right side.

8*(x + 5) = 8x + 40

Then, we write the whole equation:

8x + 47 = 8x + 40

Looking at it, we can subtract 8x from both sides, so that we're left with:

47 = 40

However, we obviously know that 47 is NOT equal to 40, so there is <em>no solution</em> for this equation.

4 0
3 years ago
Combine like terms to create an equivalent expression. Enter coefficients as simplified proper or improper fractions or integers
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Answer:

Step-by-step explanation:

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8 0
3 years ago
A bone fragment has 67% of the parent Pb-210 remaining. The half-life of Pb-210 is 22 years. How old is the bone fragment?
Korolek [52]

To solve this question we will use two important formulas.

The first formula involves the calculation of the decay constant, k which is to be found as:

k=\frac{0.6931}{T_{\frac{1}{2}}}

where T_{\frac{1}{2}} is the half life of Pb-210 which is given to be 22 years in the question.

Thus, k=\frac{0.6931}{22}\approx0.0315

Now, we will use the second formula which is called the function of decay formula and is given as:

N = N_{0} e^{-kt}

where N percentage of Pb-210 remaining in the bone at present, which in our case is 67% or 0.67

N_{0} percentage of Pb-210 to start with, which is always 100% or 1.

Plugging in all these values in the decay formula we are supposed to find the time, t.

0.67=1\times e^{-0.0315t}

Taking natural log on both sides we get:

ln(0.67)=-0.0315t

\approx-0.4005=-0.0315t

\therefore t=\frac{0.4005}{0.0315}

t\approx12.71 years

Therefore the bone fragment is about 12.71 years old.

7 0
4 years ago
Solve for z : 4z-6/4=3z+1
ruslelena [56]

Note the equal sign, what you do to one side, you do to the other side. Isolate the variable z.

First, subtract 3z and add 6/4 to both sides

4z (-3z) - 6/4 (+6/4) = 3z (-3z) + 1 (+6/4)

4z - 3z = 1 + 6/4

Simplify. Note that 1 = 4/4.

z = 4/4 + 6/4

Simplify. Combine like terms

z = 10/4

Simplify. Change the improper fraction into mixed fraction and simplify.

z = 10/4 = 2 2/4 = 2 1/2

~

7 0
4 years ago
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