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ioda
3 years ago
9

What are the 2 most common exponents you will deal with when finding roots?

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

2 and 3

Step-by-step explanation:

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Select the equation that represents the function given in the table below
marshall27 [118]

Answer:

C

Step-by-step explanation:

plug each answer into any graphing calculator until you get a graph that has the same points as the table.

3 0
3 years ago
Lithium, sodium and potassium are very reactive metals found in Group 1 on the..
Alex777 [14]

Answer:

Answer is <u>C</u>

Step-by-step explanation:

This is because Lithium =2.8.1

Sodium=2.8.8.1

<em>Valence</em><em> </em><em>electron</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>electron</em><em> </em><em>located</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>last</em><em> </em><em>shell</em>

Hope this is correct and helpful

HAVE A GOOD DAY!

4 0
3 years ago
Read 2 more answers
The mean age of 5 people in a room is 40 years. A person enters the room. The mean age is now 36. What is the age of the person
Igoryamba

Answer:

\boxed{\sf \ \ \ age = 16 \ \ \ }

Step-by-step explanation:

Hello,

as the mean age of 5 people is 40

it means that the sum of the 5 ages is 40*5=200

now a person enters the room, let's note x his age

the new mean is

\dfrac{200+x}{6}=36

200+x=6*36=216\\ x = 216-200=16\\

So the age of the new person is 16

hope this helps

6 0
3 years ago
The measures of two complementary angles are x and 2x+12. Find the measures of the angles.
Anna11 [10]

x = 26. I hope this helped

8 0
4 years ago
4. Suppose P(A) = 0.48 and P(B) = 0.62. a. Can A and B be mutually exclusive? Why or why not. b. If A and B are independent, the
kenny6666 [7]

Answer:

Step-by-step explanation:

a) Two events A,B are said to be mutually exlusive if any of the following occurs.

- A and B have an empty intersection

- A= B^c and their union is the whole sample space

- P(A intersection B) =0

REcall the following formula

P(A\cupB ) = P(A)+P(B)-P(A\cap B)

Note that P(A) + P(B) = 1.1. Since the probability is always a number between 0 and 1, it must happen that P(A\cap B) >0, otherwise, A\cup B would have a probability greater than 1. Hence, A, B are not mutually exclusive.

b) by definition, if two events are indepent, we have that the probability of the intersection is equal to products of their probabilites. Or

P(A\cap B) = P(A)P(B)

c) Recall that if we have mutuallly exclusive events A, B, then we have that  P(A\cap B)=0, if they were independent, we would have the following

P(A) P(B) =0

which necesarilly implies that at least one of the two events has 0 probability. (THis is not the case)

7 0
4 years ago
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