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FrozenT [24]
3 years ago
8

A triangle with side lengths 13, 30, and 42 is a right triangle. True or False?​

Mathematics
1 answer:
kaheart [24]3 years ago
4 0

Answer:

False

Step-by-step explanation:

42^2-30^2-13^2=695

695 ≠ 0

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Solve for x: 2x^5/3-22=464 a) x = 28 b) x = 27 c) x = ±27 d) x = ±28
Effectus [21]

Answer:

<h3>x = 27</h3>

Step-by-step explanation:

Given the expression {2x^{\frac{5}{3} }-22 = 464, we are to find the value of x in the expression. This is as shown below;

{2x^{\frac{5}{3} }-22 = 464

add 22 to both sides

{2x^{\frac{5}{3} }-22 = 464+22\\\\

{2x^{5/3} =486

divide both sides by 2

\frac{2x^{5/3}}{2} =\frac{486}{2}\\ x^{5/3} = 243

raise both sides to the power of 3/5

(x^{5/3})^{3/5} = (243)^{3/5}\\x = (\sqrt[5]{243}) ^3\\x = 3^3\\x = 27

Hence the value of x is 27

8 0
2 years ago
Whoever gets it right can have brainliest, but answer ASAP!
stellarik [79]
Answer:
10^3
Step-by-step explanation:
any time you see a number for example 7^6 you always start with those first when you have a math question like the one on the screenshot
5 0
2 years ago
Read 2 more answers
1 + 1 = <br><br>A. 1<br>B. 21<br>C. 11<br>D. fish​
Alexxandr [17]

Answer:

N/A

1 + 1 = 2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
20 divided by 2 (5+5)=
AveGali [126]
<span>The correct answer is 1.

Explanation:
The way this is written, everything after the words "divided by" would be calculated first; it is written as though this is a grouping, such as 20/(2*(5+5)). We would evaluate the innermost parentheses first; 5+5=10. Then this gives us 2*10=20 in our parentheses. 20/20 = 1.</span>
6 0
3 years ago
Help me please I need it done
Lynna [10]

Answer:

see explanation

Step-by-step explanation:

A

The circumference (C) of a circle is calculated as

C = πd ( d is the diameter ) , then

C = 3.14 × 8 ≈ 25.12 in

B

The circumference (C) of a circle is calculated as

C = 2πr ( r is the radius )

Here C = 94.2 , then

2πr = 94.2 ( divide both sides by 2π )

r = \frac{94.2}{2(3.14)} = 15 cm

4 0
2 years ago
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