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yan [13]
2 years ago
12

Solve for x (20 pts)

Mathematics
2 answers:
kolezko [41]2 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

8x - 8 + 30 = 11x -11

3x = 33

x = 11

telo118 [61]2 years ago
5 0

Answer:

x=11

Step-by-step explanation:

8x-8+30+11x-11

3x=33

x=11

hehe the same as her/him

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A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp
abruzzese [7]

Step-by-step explanation:

<em>"A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp."</em>

<em />

<em>"(a) During a morning activity of the camp, these 12 players have to randomly group into six pairs of two players each."</em>

<em>"(i) Find the total number of possible ways that these six pairs can be formed."</em>

The order doesn't matter (AB is the same as BA), so use combinations.

For the first pair, there are ₁₂C₂ ways to choose 2 people from 12.

For the second pair, there are ₁₀C₂ ways to choose 2 people from 10.

So on and so forth.  The total number of combinations is:

₁₂C₂ × ₁₀C₂ × ₈C₂ × ₆C₂ × ₄C₂ × ₂C₂

= 66 × 45 × 28 × 15 × 6 × 1

= 7,484,400

<em>"(ii) Find the probability that each pair contains players of the same gender only. Correct your final answer to 4 decimal places."</em>

We need to find the number of ways that 6 boys can be grouped into 3 pairs.  Using the same logic as before:

₆C₂ × ₄C₂ × ₂C₂

= 15 × 6 × 1

= 90

There are 90 ways that 6 boys can be grouped into 3 pairs, which means there's also 90 ways that 6 girls can be grouped into 3 pairs.  So the probability is:

90 × 90 / 7,484,400

= 1 / 924

≈ 0.0011

<em>"(b) During an afternoon activity of the camp, 6 players are randomly selected and 6 one-on-one matches with the coach are to be scheduled.</em>

<em>(i) How many different schedules are possible?"</em>

There are ₁₂C₆ ways that 6 players can be selected from 12.  From there, each possible schedule has a different order of players, so we need to use permutations.

There are 6 options for the first match.  After that, there are 5 options for the second match.  Then 4 options for the third match.  So on and so forth.  So the number of permutations is 6!.

The total number of possible schedules is:

₁₂C₆ × 6!

= 924 × 720

= 665,280

<em>"(ii) Find the probability that the number of selected male players is higher than that of female players given that at most 4 females were selected. Correct your final answer to 4 decimal places."</em>

If at most 4 girls are selected, that means there's either 0, 1, 2, 3, or 4 girls.

If 0 girls are selected, the number of combinations is:

₆C₆ × ₆C₀ = 1 × 1 = 1

If 1 girl is selected, the number of combinations is:

₆C₅ × ₆C₁ = 6 × 6 = 36

If 2 girls are selected, the number of combinations is:

₆C₄ × ₆C₂ = 15 × 15 = 225

If 3 girls are selected, the number of combinations is:

₆C₃ × ₆C₃ = 20 × 20 = 400

If 4 girls are selected, the number of combinations is:

₆C₂ × ₆C₄ = 15 × 15 = 225

The probability that there are more boys than girls is:

(1 + 36 + 225) / (1 + 36 + 225 + 400 + 225)

= 262 / 887

≈ 0.2954

7 0
2 years ago
from his house Mike rides his bike 2 miles west and 10 miles north to the gym how much shorter is it to the gym if he rode in a
Dmitry [639]
Using the rectangular route Mike rides 12 miles. If he rides diagonally the distance is √2²+10²=√4+100=√104.
The difference between the two routes is 12-√104=1.80 miles approximately.
4 0
3 years ago
Please don’t skip! Urgent! Please just give me the answers to the solution part.
svlad2 [7]

Answer:

you have selected the correct option for the first part

in the second part, the answer is "there is no solution"

in the third part, the answer is "one solution" which is (0 , 1)

brainly it if you found this helpful

8 0
2 years ago
Find the ​slope-intercept form of the equation of the line that passes through the point P and makes angle with the positive ​x-
SIZIF [17.4K]

Answer:

The answer is "y= -x+7"

Step-by-step explanation:

If \bold{\theta = 135^{\circ}}

point: p=(2,5)

Formula:

\to m= \tan \theta \\\\\to (y-y_1)= m(x-x_1)

\to m= \tan \ 135^{\circ} =  -1\\\\\to x_1= 2\\\\\to y_1=5

Put the value in the above formula:

\to y- 5 = -1(x-2)\\\\\to y- 5 = -x+2\\\\\to x+y = 5+2\\\\\to x+y=7

\to y= -x+7

3 0
3 years ago
Please help me out with this!
olganol [36]
A. y-intercept

B. The slope is 3/4, the y-intercept is 0

C. For this one you need to put it in y-intercept form. So, you subtract 2x, and move it over to 12. The equation would look like 6y = 2x + 12.

Then, divide everything by 6, and the equation would look like: y = 2/6x + 2

Thus, the slope is 2/6x and 2 is the y-intercept.
3 0
2 years ago
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