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2 years ago

Solve for x (20 pts)

Mathematics

2 answers:

kolezko [41]2 years ago

7 0

Answer:

x = 11

Step-by-step explanation:

8x - 8 + 30 = 11x -11

3x = 33

x = 11

telo118 [61]2 years ago

5 0

Answer:

x=11

Step-by-step explanation:

8x-8+30+11x-11

3x=33

x=11

hehe the same as her/him

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2 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

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3 years ago

Beyonce danced around the track tree times. The track was 400 meters. How many kilometers did she dance all together

IRISSAK [1]

Answer: 1,200,000

Step-by-step explanation

1 meter is 1000 kilometers and the track is 400 meters long, so you must multiply 400*1000=400,000

She danced around 3 times s you must multiply 400,000*3=1,200,000

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2 years ago