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Gnesinka [82]
3 years ago
11

A JIT system uses kanban cards to authorize movement of incoming parts. In one portion of the system, a work center uses an aver

age of 111 parts per hour while running. The manager has assigned an inefficiency factor of .21 to the center. Standard containers are designed to hold 5 dozen parts each. The cycle time for parts containers is about 100 minutes.How many containers are needed?
Business
1 answer:
ycow [4]3 years ago
4 0

Answer: 4 containers

Explanation:

The formula used to get the number of containers that are needed will be:

N = DT(1+X)/C

where,

N = total containers

D = planned usage rate used by the work center = 111 parts per hour

T = average waiting time = 100 minutes = 100/60 hours = 1.67 hours

X = inefficiency factor = 0.21

C = capacity of standard container = 5 dozens = 5 × 12 = 60 parts

N = DT(1+X)/C

N = (111 × 1.67)(1 + 0.21)/60

N = (185.37 × 1.21)/60

N = 224.2977/60

N = 3.738

N = 4 approximately

4 containers will be needed

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