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choli [55]
3 years ago
10

Please Help!! Thank you so much!!

Mathematics
1 answer:
STatiana [176]3 years ago
6 0
It’s the last one 7 sqrt5+8sqrt2/27
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Trigonometry
Nadusha1986 [10]

55° is equal to 0.9599 radians.  

Step-by-step explanation:  

Step 1:  

If an angle is represented in degrees, it will be of the form x°.  

If an angle is represented in radians, it will be of the form \frac{\pi}{x}radians.  

To convert degrees to radians, we multiply the degree measure by \frac{\pi}{180}.

For the conversion of degrees to radians,

the degrees in radians = (given value in degrees)(\frac{\pi}{180}).

Step 2:

To convert 50°,  

55\left(\frac{\pi}{180}\right)=\frac{55\pi}{180}.

0.3055 (\pi) =0.9599 radians.

So 55° is equal to 0.9599 radians.

7 0
3 years ago
Read 2 more answers
2m = 1 + m what do I need to do to solve
devlian [24]

So all you need to do is subtract m from both sides.

Then you have your answer

m = 1

I hope this helps

-ayden

4 0
3 years ago
Read 2 more answers
A local park is in the shape of a square. A map of the local park is made with the scale 1 inch to 200 feet. If a straight path
kkurt [141]

Answer:

600 ft per side

Step-by-step explanation:

1 in = 200 feet

12 in = 1 foot

12 in * 200 ft= 2400 ft

2400/4 = 600 ft per side

5 0
3 years ago
Mr. Gordon weighs 205 pounds . Multiply his earth weight by 0.91 to find out how much he would weigh on the planet Venus. What i
Savatey [412]
When you multiply 205 by 0.91 you get 186.55 and 205 minus 186.55 is 18.45
5 0
3 years ago
Simplify this please​
Ugo [173]

Answer:

\frac{12q^{\frac{7}{3}}}{p^{3}}

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. (a^{x})^{n} = a^{xn}

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). a^{-x} = \frac{1}{a^{x}}, and to help with this question: \frac{a^{-x}b}{1} = \frac{b}{a^{x}}.

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. (a^{x})(a^{y}) = a^{x+y}

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. \frac{a^{x}}{a^{y}} = a^{x-y}

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}

\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}        Distribute exponent

=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}        Simplify each exponent by multiplying

=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}        Negative exponent rule

=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}        Combine the like terms in the numerator with the base "q"

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}        Rearranged for you to see the like terms

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}        Multiplying exponents with same base

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}        2 + 1/3 = 7/3

=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}        Fractional exponents as radical form

=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.

=\frac{(4)(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Multiply 4 and 3

=\frac{12pq^{\frac{7}{3}}}{p^{4}}        Dividing exponents with same base

=12p^{(1-4)}q^{\frac{7}{3}}        Subtract the exponent of 'p'

=12p^{(-3)}q^{\frac{7}{3}}        Negative exponent rule

=\frac{12q^{\frac{7}{3}}}{p^{3}}        Final answer

Here is a version in pen if the steps are hard to see.

5 0
3 years ago
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