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choli [55]
3 years ago
10

Please Help!! Thank you so much!!

Mathematics
1 answer:
STatiana [176]3 years ago
6 0
It’s the last one 7 sqrt5+8sqrt2/27
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skelet666 [1.2K]

Step-by-step explanation:

y = x + 2

X. <u>Y</u>

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Based on this table, the graph that best represents the table is the one on the right.

7 0
3 years ago
9 times a number increased by 2
sladkih [1.3K]

Answer:

9x + 2

Step-by-step explanation:

Because you are multiplying an unknown number by 9, it would be considered 9*x or 9x.

Then, you add 2, because when you increase in math, you are adding.

Therefore, the final product is 9x + 2.

5 0
4 years ago
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Math question screen shot down below
ser-zykov [4K]

Answer:

11

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11,16,12,7,23,9,5,5

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3 0
3 years ago
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Consider the logarithms base 5. For each logarithmic expression below, either calculate the value of the expression or explain w
Tom [10]

Answer:

log₅(3125) = 5

Step-by-step explanation:

Given:

log₅(3125)

Now,

using the property of log function that

logₐ(b) = \frac{\log(b)}{\log(a)}

thus,

Therefore, applying the above property, we get

⇒ \frac{\log(3125)}{\log(5)}   (here log = log base 10)

now,

3125 = 5⁵

thus,

⇒  \frac{\log(5^5)}{\log(5)}

Now,

we know from the properties of log function that

log(aᵇ) = b × log(a)

therefore applying the above property we get

⇒ \frac{5\log(5)}{\log(5)}

or

⇒ 5

Hence,

log₅(3125) = 5

8 0
3 years ago
What is continuous​ compounding? how does the apy for continuous compounding compare to the apy​ for, say, daily​ compounding? e
aliya0001 [1]
Continuous compounding is the mathematical limit that compound interest can reach.

It is the limit of the function A(1 + 1/n) ^ n as n approaches infinity. IN theory interest is added to the initial amount A  every infinitesimally small  instant.
The limit  of (1 + 1/n)^n is the number e ( = 2.718281828 to 9 dec places).

Say we invest  $1000  at daily compounding at yearly interest of 2 %. After 1 year the $1000 will increase to:-

1000 ( 1 + 0.02/365)^365 = $1020.20

with continuous compounding this will be 

1000 * e^1  =  $2718.28  
4 0
3 years ago
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