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Salsk061 [2.6K]
3 years ago
13

SOFTWARE A software company releases two products: a home version of their photo editor, which costs $20, and a professional ver

sion, which costs $45. The company sells 1000 copies of the photo editing software, earning total revenue of $38,075. Write and solve a system of equations to determine how many home versions and professional versions of the software the company sold. Let h = the number of home versions sold and p= the number of professional versions sold.
Mathematics
1 answer:
GaryK [48]3 years ago
6 0

The software company released 227 home versions and 723 professional versions.

<h3>Equation</h3>

Let  h represent the number of home versions sold and p represent the number of professional versions sold.

Since 1000 copies where sold, hence:

  • x + y = 1000    (1)

Also the revenue was $38075, hence:

  • 20h + 45p = 38075     (2)

Solving equations 1 and 2 simultaneously gives:

h = 227, p = 723

The software company released 227 home versions and 723 professional versions.

Find out more on equation at: brainly.com/question/13763238

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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

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Answer:

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