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yawa3891 [41]
4 years ago
5

11^-x+3=5^-3x. solve for x write the exact answer using base -10 logarithms

Mathematics
1 answer:
jeyben [28]4 years ago
8 0

Hi,

11^{-x+3}=5^{-3x}\\\\(-x+3) log 11 = -3x log 5\\\\-x*log 11 + 3x* log 11 =-3*log 11\\\\x(-log 11 +3 log 5)=-3 log 11\\\\x=\dfrac{-3 log 11}{(3 log 5 -log 11} \\\\x=-2.959854....

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What is the answer to this solution. -7r−4≥ 4r+2
tia_tia [17]

Answer:

The solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

-7r-4\ge \:4r+2

Add 4 to both sides

-7r-4+4\ge \:4r+2+4

Simplify

-7r\ge \:4r+6

Subtract 4r from both sides

-7r-4r\ge \:4r+6-4r

Simplify

-11r\ge \:6

Multiply both sides by -1 (reverses the inequality)

\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)

Simplify

11r\le \:-6

Divide both sides by 11

\frac{11r}{11}\le \frac{-6}{11}

Simplify

r\le \:-\frac{6}{11}

Therefore, the solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

7 0
3 years ago
1000 grams decreased by 94
muminat
906 grams.
1000-94=906 grams
4 0
4 years ago
Dentify all the pairs of vertical angles in the figure.<br><br> Pair#1:<br><br> Pair#2
Brilliant_brown [7]
Ok so the only ones that we know for sure are 4 = 1, 6=8, 7=9 and you can’t really do all that much with 2,3,5 because it’s not as obvious
3 0
3 years ago
If f(x) = x^4-x^3+x^2 and g(x)= -x^2, where x does not = 0, what is (f/g)(x)?
Korvikt [17]

For this case we have the following functions:

f (x) = x ^ 4-x ^ 3 x ^ 2\\g (x) = - x ^ 2

By definition of composition of functions we have to:(f \ g) (x) = \frac {f (x)} {g (x)}

So:

\frac {f (x)} {g (x)} = \frac {x ^ 4-x ^ 3 x ^ 2} {- x ^ 2} = \frac {x ^ 4} {- x ^ 2} +\frac {-x ^ 3} {- x ^ 2}+ \frac {x ^ 2} {- x ^ 2} =

By definition of division of powers of the same base we have to place the same base and subtract the exponents:

\frac {f (x)} {g (x)} = - x ^ 2+x-1

ANswer:

(\frac {f} {g}) (x) = - x ^ 2 +x-1

3 0
3 years ago
A plumber charges 130 to start job plus 56 per hour . How many hours did she work if the total bill is 214
iragen [17]

Answer:

The plumber worked for 1.5 hours

Step-by-step explanation:

y = 130 + 56x

Substitute 214 for y in the equation

214 = 130 + 56x

-130   -130                      Subtract 130 from both sides

84 = 56x                         Divide both sides by 56

1.5 = x

4 0
3 years ago
Read 2 more answers
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