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Over [174]
3 years ago
7

X

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

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Someone pls help me ill give out brainliest pls don’t answer if you don’t know
IceJOKER [234]

Answer:

h

Step-by-step explanation:

square root of 260 is 16.1 therefore h is the closest

4 0
2 years ago
Read 2 more answers
In the following diagram HI || JK.<br><br>What is the measure of x?​
otez555 [7]

Answer:

64

Step-by-step explanation:

60 + 56 + x = 180

116 + x = 180

x = 180 - 116

x = 64

7 0
3 years ago
Read 2 more answers
Tammy received a $70 gift card for a coffee store. She used it in buying some coffee that cost $8.41 per pound. After buying the
Ivahew [28]

Total money Tammy has = $70

Money she is left with now = $19.54

Therefore, the money she used on coffee =

70 - 19.54 = $50.46

Now,

1 pound coffee costs $8.41

Pounds of coffee she bought = 50.46 ÷ 8.41

= 6 pounds

7 0
2 years ago
Help me please<br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20ln%28x%20%7B%20%7D%20%5E%7B2%7D%20%2B%202%20%29%20" id="
CaHeK987 [17]
➡Answer: x=√(e^y-2)

❇Explanation:
Step1: Let f(x)=y,then

↪y=ln(x²+2)

Step2: Converting it into exponential form,

↪e^y=x²+2

↪x²=e^y-2

Step3: Taking square root of both sides,

↪x=√(e^y-2)

❇Note:

ln means log with base e.

So in step 2 , base e of ln (x²+2) goes to other side in the form e^y. That is simply the property of log I used there..

Hope this helps!
3 0
3 years ago
Compute the lower Riemann sum for the given function f(x)=x2 over the interval x∈[−1,1] with respect to the partition P=[−1,− 1
Nata [24]

Answer:

21/64

Step-by-step explanation:

First, we need to note that the function f(x) = x² is increasing on (0, +∞), and it is decreasing on (-∞,0)

The first interval generated by the partition is [-1, -1/2], since f is decreasing for negative values, we have that f takes its minimum values at the right extreme of the interval, hence -1/2.

The second interval is [-1/2, 1/2]. Here f takes its minimum value at 0, because f(0) = 0, and f is positive otherwise.

Since f is increasing for positive values of x, then, on the remaining 2 intervals, f takes its minimum value at their respective left extremes, in other words, 1/2 and 3/4 respectively.

We obtain the lower Riemman sum by multiplying this values evaluated in f by the lenght of their respective intervals and summing the results, thus

LP(f) = f(-1/2) * ((-1/2) - (-1)) + f(0) * (1/2 - (-1/2)) + f(1/2)* (3/4 - 1/2) + f(3/4) * (1- 3/4)

= 1/4 * 1/2 + 0 * 1 + 1/4 * 1/4 + 9/16 * 1/4 = 1/8 + 0 + 1/16 + 9/64 = 21/64

As a result, the lower Riemann sum on the partition P is 21/64

3 0
3 years ago
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