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3 years ago

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Mathematics

1 answer:

ziro4ka [17]3 years ago

7 0

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

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The second number in an ordered pair of numbers that corresponds to a point on a coordinate system is the ?

Ksivusya [100]

Answer:

See below.

Step-by-step explanation:

The y-coordinate , giving the value of the function at this point. It is a part of the range of the function.

3 0

3 years ago

It is not B so plz help me

11111nata11111 [884]

Answer:

The picture is blocked out D:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

ben needs to convert 500 US dollars to the japanese yen. one american dollar is worth 123.3 yen. how many yen will he have

laiz [17]

Answer:

<u>The correct answer is 61,650 Yens</u>

Step-by-step explanation:

US$ in cash that Ben has = 500

Exchange rate (US$/Yen) = 1 : 123.3

For calculating the total amount in Yens that Ben has, we use this formula:

Yens in Cash = US$ in Cash * Exchange rate given

Yens in Cash = 500 * 123.3

Yens in Cash = 61,650

<u>After converting the US$ 500 Ben has, he will receive Yens 61,650</u>

6 0

3 years ago

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

vesna_86 [32]

First you distribute the 3
(3x-12) (x+5)=0
then you set each equation equal to zero
3x-12=0 & x+5=0
then you solve for x
x =4, -5

7 0

3 years ago

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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

3 years ago