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Temka [501]
4 years ago
14

How can I round2,605 to the nearest hundred

Mathematics
2 answers:
bogdanovich [222]4 years ago
7 0
Four below let it go five above give it a shove so the number turns into 2,600
gulaghasi [49]4 years ago
7 0

2,600 :) 605 closer to 600 than 700

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Find the equation of the straight line passing through the points (4; 2) and (2; 4).
Alecsey [184]
Use point-slope form.

But first let's find the slope.

(4, 2), (2, 4)

m = y2-y1/x2-x1

m = (4 - 2)/(2 - 4)

m = 2/-2

m = -1

So this is the slope, now we can plug this into the equation along with any point.

y - y1 = m(x - x1)

Where y1 is the y-value of the point, x1 is the x-value, and 'm' is the slope.

Let's plug in point (4, 2):

y - 2 = -1(x - 4)

This can be one of your options.

Distribute -1:

y - 2 = -x + 4

Add 2 to both sides:

y = -x + 6

This can be another of your options.

Add 'x' to both sides:

x + y = 6

This can be another of your options.
8 0
3 years ago
Read 2 more answers
If x(f) = x5 and g(x) = -2-3x2 , which is f(g(x))
mel-nik [20]
At least 20 characters long
5 0
4 years ago
A camera manufacturer spends $2,000 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell
hjlf
A) let the number of cameras sold per day for breakeven be x

Total daily cost = 2000 + 9x

Total daily revenue = 17x

therefore for just covering expenses both cost and revenue must be equal

2000 + 9x = 17x

2000 = 17x - 9x = 8x

x = 2000/8 = 250 cameras


b) increasing production by 50 cameras per day will give a daily profit of;

50 * (17 - 9) = 50 * 8 = $400 (seeing that the fixed daily cost of $2000 remains unchanged)


It's a
6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
olchik [2.2K]

Answer:

1)(2m^2-4m)/2(m-2) = m (fourth blank)

2)m^2-2m+1/m-1= m-1 (second blank)

3)m^2-3m+2/m^2-m= (m-2)/m (first blank)

4)m^2-m-2/m^2-1=(m-2)/(m-1)    (third blank)

Step-by-step explanation:

1)

(2m^2-4m)/2(m-2)

=[2m(m-2m)]/2(m-2)

= 2m/2

=m

2)

m^2-2m+1/m-1

= (m-1)^2/(m-1)

=(m-1)(m-1)/(m-1)

=(m-1)

3)

m^2-3m+2/m^2-m

=m^2-m-2m+2/m(m-1)

=m(m-1)-2(m-1)/m(m-1)

= (m-1)(m-2)/m(m-1)

=(m-2)/m

4)

m^2-m-2/m^2-1

=m^2+m-2m-2/(m+1)(m-1)

=m(m+1)-2(m+1)/(m+1)(m-1)

=(m+1)(m-2)/m+1)(m-1)

=(m-2)/(m-1) !

5 0
3 years ago
Error analysis
Bas_tet [7]
2(2x-1) + 2(3x)=4x-2+6x = 10x - 2 & not <span>=10x-1</span>
8 0
4 years ago
Read 2 more answers
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