Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
Answer:
Step-by-step explanation:
AB = 5
AC = 6
BC = √(5² + 6²) = √61 ≈ 7.8 units
If you simplify the expression you will get 18x - 15.
Answer:
90
Step-by-step explanation:
Hey there ;-)
It will be <u>-13</u>,
as the other numbers can also be there in the inner circle.
<em>By </em><em>Benjemin</em> ☺️