30 miles (104-74). Or 104 if the first 74 miles was not on the turnpike xd
Answer:
KL= 17.67 unit
UE = 17.67 unit
Step-by-step explanation:
Given:
Diagonals
KL= h+7
UE = 4h-25
Find:
Length of diagonals KL and UE
Computation:
We know that in isosceles trapezoid the length of diagonals are equal
So,
KL = UE
h+7 = 4h-25
3h = 32
h = 10.67
So,
KL= h+7
KL= 10.67+7
KL= 17.67 unit
UE = 4h-25
UE = 4(10.67)-25
UE = 17.67 unit
Answer:
because she usually gets lower scores but her avarge is 13 because she make 30 in one game witch is an outlire
Step-by-step explanation:
if im wrong im sorry if not pls brainlyest
Answer:
130°
Step-by-step explanation:
In the picture attached, the rectangle can be seen.
We know that m∠BAC = 50°, then m∠ADB is also 50°. m∠AOE must be 180° - 90° - 50° = 40°, and m∠OAD = 90° - 50° = 40°, then m∠DOA = 180° - 40° - 50° = 90°. Finally m∠EOD = m∠DOA + m∠AOE = 90° + 40° = 130°
Answer:
The height of the tree is 14.85
m
Step-by-step explanation:
The length of the shadow cast by the tree = 25 m
The length of the shadow cast by the signpost = 6 m
The height of the signpost = 3.5 m
Therefore, by similar triangles, we have;
Let θ, represent the angle formed by the line extending a line from the tip of the shadow, to the tip of the object and let x represent the height of the tree, we have
Tan(θ) = Opposite/Adjacent = Height of the object/(The length of the shadow)
∴ Tan(θ) = 3.5/6 = x/25
x = 25 × 3.5/6 = 14.58
The height of the tree = x = 14.85
m