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3 years ago

Solve the equation below for x. −12(3x−4)=11 A. −1323 B. −813 C. −6 D. 6

Mathematics

1 answer:

geniusboy [140]3 years ago

3 0

-1/2( 3x -4) = 11

Use distributive properties:

-3/2 + 2,= 11

Subtract 2 from both sides:

-3/2x = 9

Divide both sides by -3/2

X = 9/ -3/2

X = -6

The answer is c. -6

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Martin burns 360 calories running for 30 minutes. Paul burns 165 calories for every 15 minute he runs. If Kara runs for 20 minut

Yanka [14]

Answer: She would have to burn between 220 and 240 calories per minute to have a calorie burn rate between those of Martin and Paul.

Step-by-step explanation:

Martin:

360 calories / 30 min = 12 calories/min

Paul:

165 calories / 15 min = 11 calories/min

Kara:

Needs to burn between 11 and 12 calories/min, so we'll calculate the range:

11 calories/min x 20 min = 220 calories (minimum # calories she can burn)

12 calories/min x 20 min = 240 calories (maximum # calories she can burn)

7 0

3 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

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3 0

3 years ago

Read 2 more answers

What is the product?

ad-work [718]

Answer is C, just multiply and expand.