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hram777 [196]
3 years ago
6

Solve the equation below for x. −12(3x−4)=11 A. −1323 B. −813 C. −6 D. 6

Mathematics
1 answer:
geniusboy [140]3 years ago
3 0

-1/2( 3x -4) = 11

Use distributive properties:

-3/2 + 2,= 11

Subtract 2 from both sides:

-3/2x = 9

Divide both sides by -3/2

X = 9/ -3/2

X = -6

The answer is c. -6

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Answer: A negative

Step-by-step explanation:

The opposite of a negative is positive, the opposite of a positive is a negative.

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OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
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Explanation:

Factors of 18:

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Factors of 21:

1, 3, 7.

The highest number that both sets contain is 3, so the GCF will be 3.


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