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Anna007 [38]
2 years ago
14

It’s pre algebra finding y axis help with slope

Mathematics
1 answer:
Assoli18 [71]2 years ago
6 0
(0,-2) , good luck >>>>>>>>>
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Can u help me. where do u plot it. what is x and what is y
goldenfox [79]

Answer:

Step-by-step explanation:

for the first equation x= -2 and y=-7

the second equation x=3 and y is 3 now just plot x and y from the same equation on the same line

7 0
3 years ago
Read 2 more answers
How much would $300 invested at 4% interest compounded monthly be
Anna11 [10]

Answer:

$412.92

Step-by-step explanation:

You are going to want to use the compound interest formula, which is shown below.

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance </em>

<em>r = interest rate </em>

<em>n = number of times compounded annually </em>

<em>t = time </em>

<em />

The first step is to change 4% into its decimal form:

4% -> \frac{4}{100} -> 0.04

Now plug in the values:

A=300(1+\frac{0.04}{12})^{(12)8}

A=412.92

It would  be worth $412.92

8 0
3 years ago
Lee watches tv 3hours per day. Lee tv consumes 200 watts when on. Electricity cost 12 cents 1 kilowatt-hour how much does Lee's
Alik [6]

Answer: $2.16

Lee watches TV 3 hours per day and TV consumes 200 watts.

Cost of electricity = 12 cents/(1-kilowatt-hour)

200w×3 hours

600 watt-hours

1000 watt-hours=1kwh

1 watt-hours= 1/1000 kwh

600 watt-hours 600/1000=0.6 kwh

0.6×12=7.2cents

1 day=7.2 cents

30 days

7.2×30

216 cents

$2.16

3 0
3 years ago
Read 2 more answers
Can someone find the total area of this poster
xeze [42]

Answer: 1,360

Step-by-step explanation:

20 * 20 = 400

20 * 12 = 240

240 * 4 = 960

960 + 400 = 1,360

7 0
3 years ago
suppose the leftmost digits of two numbers are 8 and 3. can you tell which number is greater? explain.
Debora [2.8K]
You cannot tell which number is greater because you don't know how many numbers follow after 8 or 3. It all depends on how many numbers follow afterwards.
Example: 
It could be 800 or 80,000
It could be 30,000 or 300,000

~ I hope you get what I mean. If you have any more questions, I'd be happy to help!<span />
6 0
3 years ago
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