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Andrew [12]
3 years ago
6

Solve for w. -12 = -9w​

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0

Answer:

4/3 = w

Step-by-step explanation:

Step 1: Write equation

-12 = -9w

Step 2: Divide both sides by -9

4/3 = w

pashok25 [27]3 years ago
4 0
-12=-9w

u divide -12 by -9 and you get 1.3 so therefor w=1.3
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\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet

\frak{Good\;Morning!!}

\pmb{\tt{Question\;1}}

                 \star\boldsymbol{\rm{Given-:}}

  • Side length = 7 cm,
  • Side length = 5 cm.

              \star\boldsymbol{\rm{We're\;looking\;for-:}}

  • Side length = x

This is how it's done.

         

\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet

There's a <u>special formula</u> that <u>we can use</u> if we need to find the longest side of a right triangle. Fortunately, <u>all of these triangles are right ones! </u>Good.

The <u>formula</u> is. \boldsymbol{\rm{a^2+b^2=c^2}}. This formula is known as Pythagoras' Theorem. This formula only works for right triangles.

Since we <u>have a and b</u>, we <u>can just put in the values</u> (7 for a and 5 for b), And then simplify!

\boldsymbol{\rm{7^2+5^2=c^2}} | 7^2 simplifies to 49, and 5^2 simplifies to 25

\boldsymbol{\rm{49+25=c^2}}. | add

\boldsymbol{\rm{74=c^2}} | square root both sides

\boldsymbol{\rm{8.6=c}}}. | the <u>answer is given to 1 decimal place</u>, as the problem required

\orange\hspace{350pt}\above5

\pmb{\tt{Question\;2}}

 Once more, we're given two sides, and asked to find the third one,  

  which is still the longest side.

\boldsymbol{\rm{a^2+b^2=c^2}} is still the formula used here

Put in 5 for a and 3 for b.

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\boldsymbol{\rm{25+9=c^2}} | add

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\hspace{350pt}\above5

\pmb{\tt{Question\;3}}

This problem is solved the exact same way

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\orange\hspace{300pt}\above2

\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet\equiv\bullet

\pmb{\tt{Question4}}

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\pmb{\tt{Question\;5}}

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