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Svetlanka [38]
3 years ago
5

Prove the identity: [(tanx)/(1-cosx) ] = [(cscx)(1+secx)]

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0
tan x / ( 1 - cos x ) =
= \frac{ \frac{sinx}{cosx} }{1-cos x}= \\ = \frac{sin x}{( 1 - cos x ) cos x}* \frac{1+cosx}{1+cos x}= \\  =\frac{sin x(1+cos x)}{sin^{2} xcos x}= \\  =\frac{1+cos x}{sin x cos x}= \frac{1}{sin x}* \frac{1+cos x}{cos x}= \\ =csc x *(1+ \frac{1}{cos x})=
= csc x * ( 1 + sec x )
( correct )
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