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3 years ago

Katya has several sources of income, listed in the table. Which are considered earned income? *Select all that apply.**

Mathematics

1 answer:

Lady_Fox [76]3 years ago

3 0

Answer: $1300 per month salary

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Please answer this multiple choice question correctly for 30 points and brainliest!!

marishachu [46]

Step-by-step answer:

Given:

Initial monthly salary = $5000

New salary = 10% less

Salary a year after = 15% more

Solution:

New salary

= 5000 * (100-10)%

= 5000 * 90%

= 5000 * 90/100

= 4500

Salary a year after

= 4500 * (100+15%)

= 4500 * 115%

= 4500 * 115/100

= 45*115

= 5175

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3 years ago

Help please I don’t understand probability and need the correct answers to these questions.

vampirchik [111]

Answer:

1) = 0.175

2) = 0.244

3) = 0.168

Step-by-step explanation:

Experimental, not theoretical, so we use the results table.

1. P(3 n Tails) = 62/(53 + 65 + 49 + 71 + 54 + 62) = 0.175

2. P(Woman n Up) = 39/(36 + 43 + 39 + 42) = 0.244

3. P(Tuna n Wheat Bread) = 23/(22 + 24 + 21 + 22 + 25 + 23) = 0.168

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3 years ago

A quadrilateral has interior angle measures of 65°, 75°, and 121°. What is the measure of the fourth interior angle in the quadr

harina [27]

The measure of the fourth interior angle in the quadrilateral is 145

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3 years ago

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9r+4d-2 use r=9 and d=2

Leto [7]

Answer:

Step-by-step explanation:

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3 years ago

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In an analysis of healthcare data, ages have been rounded to the nearest multiple of 5 years. The difference between the true ag

Mars2501 [29]

Answer:

The approximate probability that the mean of the rounded ages within 0.25 years of the mean of the true ages is P=0.766.

Step-by-step explanation:

We have a uniform distribution from which we are taking a sample of size n=48. We have to determine the sampling distribution and calculate the probability of getting a sample within 0.25 years of the mean of the true ages.

The mean of the uniform distribution is:

$\mu=\dfrac{Max+Min}{2}=\dfrac{2.5+(-2.5)}{2}=0$

The standard deviation of the uniform distribution is:

$\sigma=\dfrac{Max-Min}{\sqrt{12}}=\dfrac{2.5-(-2.5)}{\sqrt{12}}=\dfrac{5}{3.46}=1.44$

The sampling distribution can be approximated as a normal distribution with the following parameters:

$\mu_s=\mu=0\\\\\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.44}{\sqrt{48}}=\dfrac{1.44}{6.93}=0.21$

We can now calculate the probability that the sample mean falls within 0.25 from the mean of the true ages using the z-score:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{0.25-0}{0.21}=\dfrac{0.25}{0.21}=1.19\\\\\\P(|X_s-\mu|$

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3 years ago

Katya has several sources of income, listed in the table. Which are considered earned income? *****Select all that apply.******

Katya has several sources of income, listed in the table. Which are considered earned income? *Select all that apply.**