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3 years ago

8

An equation that results in a true statement has infinitely many solutions. Does the equation below have infinitely many solutio

ns?
3(2+x) =3x+6

1 answer:

Zarrin [17]3 years ago

7 0

No, it’s equal to each other

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Write as a decimal number.<br> 9-10

Ad libitum [116K]

Answer:

.9

Step-by-step explanation:

9 divided by 10

8 0

3 years ago

An exterior angle of a triangle measures 110°. One of the interior opposite angle measures 50°. Then the other interior opposite

saw5 [17]

Answer:

60°

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the 2 interior opposite angles.

let the other interior angle be x, the

x + 50 = 110 ( subtract 50 from both sides )

x = 60

Thus the other interior opposite angle is 60°

5 0

3 years ago

Read 2 more answers

Anita collects shells and stones in a ratio of 1:2.

omeli [17]

Answer:

The answer is 16 stones

Step-by-step explanation:

It's 8:16 because

8/1 = 8

and

2 x 8 = 16

To check your answer to see if its correct :

1/2 = 2

16/2=8

Hope this helps!! ;)

8 0

2 years ago

If one line has a slope of 2/3, then the slope of a line parallel to it would be?

ipn [44]

-3/2

perpendicular slopes are those that are opposite sign and reciprocal of the original given slope

8 0

3 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

3 years ago