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3 years ago

Do these look right?

Mathematics

1 answer:

bezimeni [28]3 years ago

5 0

Answer:

yes it look right like the one you have to do 2x+5=39

You might be interested in

Evaluate 2times 8+5-18divided by3

Taya2010 [7]

Answer:

Step-by-step explanation:

PEMDAS (order of operations)

2 times 8=16

18/3= 6

16+5-6=15

4 0

3 years ago

If an ant runs randomly through an enclosed

liraira [26]

The area of a circle is π (radius²)

The area of the outer (2-ft) circle is π (2²) = 4 π square feet.

The area of the inner (1-ft) circle is π (1²) = 1 π square feet.

The inner circle covers 1/4 of the area of the outer circle.

So if the ant wanders around totally aimlessly and randomly, and there's no way to
know where he came from, where he is now, or where he's going next, and there's
an equal chance of him being anywhere in the big circle at any time, then there's a
25% chance of him being inside the small circle at any time, because 1/4 of the
total area is in there.

That's choice c).

4 0

3 years ago

A taxi cab in myrtle beach charges $2 per mile and $1 for every person. If a taxi cab ride for two people costs $12, how far did

oksian1 [2.3K]

Answer:

5 Miles

Step-by-step explanation:

5 Miles = 1 Miles = $2 X 5 = $10

1 Person = $1

Therefore 2 People = $1 X 2

7 0

3 years ago

-0.125 as a fraction

kaheart [24]

Answer:

-1/8

Step-by-step explanation.

125 x 8 = 1000

.125 x 8 = 1

-.125 x 8 = -1

-1/8

8 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago