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ANTONII [103]
3 years ago
13

Write 3 differences between Virtual reality and Augmented reality

Computers and Technology
2 answers:
nekit [7.7K]3 years ago
7 0

Answer:

In vr you in a vurtial world

pickupchik [31]3 years ago
7 0
- Virtual reality is usually delivered to the user through a head-mounted or hand-held controller, while augmented reality is being used more in mobile devices such as laptops and smartphones

- Augmented reality displays virtual elements to the real world while virtual reality offers a digital recreation of a real life setting

- Augmented reality is mostly used for demonstrations, interior design and mapping, while virtual reality is more used in games, medicine, military, etc

Hope this helps :)
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True or false over the course of ecological succession,species diversity increases over time?
Romashka [77]
Yes becasue the diversity usually increases over time
8 0
3 years ago
Read 2 more answers
rite a program that prompts the user to enter an integer and displays each of its numbers one by one.
LenaWriter [7]

Answer:

#include <iostream>

using namespace std;

int main()

{

   int num;

   cout<<"Enter the integer: ";

   cin>>num;

   

   while(num>0){

       

       int rem = num%10;

       cout<<rem<<endl;

       num = num/10;

       

   }

}

Explanation:

First include the library iostream in the c++ programming for input/output.

Then write the main function and declare the variable.

cout is used to display the message on the screen.

cin is used to store the value in the variable.

then used the while loop and put the condition num>0

after that, take the reminder of the number by using the operator modulus '%'.

and then print it on the screen.

after that reduce the number by one digit.

This process continue until the condition not failed.

Therefore, the all digits of the number will be printed.

8 0
4 years ago
Ask the user to input their grade percentage (e.g. the use will enter 98 if they had an overall grade of 98% in their course) fo
Airida [17]

Answer:

In Python

def getpointValue(subject):

   if subject >= 75:        point = 4; grade = 'A'

   elif subject >= 60:        point = 3; grade ='B'

   elif point >= 50:        point = 2; grade = 'C'

   elif point >= 40:        point = 1; grade = 'D'

   else:        point = 0; grade = 'F'

   return point,grade

subjects= ["Accounting","Marketing","Economics","MIS"]

acct = int(input(subjects[0]+": "))

mkt = int(input(subjects[1]+": "))

eco = int(input(subjects[2]+": "))

mis = int(input(subjects[3]+": "))

acctgrade = getpointValue(acct)

print(subjects[0]+" Grade: "+str(acctgrade[1]))

mktgrade = getpointValue(mkt)

print(subjects[1]+" Grade: "+str(mktgrade[1]))

ecograde = getpointValue(eco)

print(subjects[2]+" Grade: "+str(ecograde[1]))

misgrade = getpointValue(mis)

print(subjects[3]+" Grade: "+str(misgrade[1]))

totalpoint = (acctgrade[0] + mktgrade[0] + ecograde[0] + misgrade[0]) * 3

gpa = totalpoint/12

print("GPA: "+str(gpa))

Explanation:

<em>The solution I provided uses a function to return the letter grade and the point of each subject</em>

<em>I've added the explanation as an attachment where I used comment to explain difficult lines</em>

<em />

Download txt
6 0
3 years ago
Cost, time, knowledge are examples of
Katena32 [7]
They are examples of constraints.
8 0
3 years ago
Assume that scotus is a two-dimensional character array that stores the family names (last names) of the nine justices on the Su
dangina [55]

Answer:

for (int i = 0; i < 9; ++i) {

int k = 0;

while (k < 20 && scotus[i][k] != '') {

cout << scotus[i][k];

k++; }

cout << "\n"; }

Explanation:

scotus here is a two dimensional array. It contains names of 9 justices. so the loop starts from 0 and ends when i points to the last name element in the array. Then a while loop is used to check that name is longer than twenty characters and will keep on printing each output on the separate line.

Another way to write this:

for (int i = 0; i < 9; i++){

cout << scotus[i] << "\n"; }

This loop will keep on executing and printing the names of the nine justices at every iteration until it reaches the end of the array (last element of the array scotus).

5 0
3 years ago
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