Answer:
Omg tysm have a great day!
Answer:
The answer should be C. I, II, IV
Answer:
Required code is given below:
Explanation:
monitor bounded buffer {
int items[MAX ITEMS];
int numItems = 0;
condition full, empty;
void produce(int v)
{
while (numItems == MAX ITEMS) full.wait();
items[numItems++] = v;
empty.signal();
}
int consume()
{
int retVal;
while (numItems == 0) empty.wait();
retVal = items[--numItems];
full.signal();
return retVal;
}
}
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Answer:
Uh I don't understand what you said.
Explanation:
N/A
