In this question, we can determine Maggie car initial speed (15m/s), final speed(0m/s) and the time her car moves (2.5s). Then to calculate the distance she travels, we need to multiply the average speed with time. The equation would be:
Distance traveled= (initial speed+final speed)/2 x time
Distance traveled= (0m/s + 15m/s)/2 x 2.5 second= 7.5m/s x 2.5s= 18.75m
Answer:
W' = 54.4 pounds
Step-by-step explanation:
Given that,
The weight of a bag of books = 40 pounds
After picking up some books at school, the weight has increased by 36%.
We need to find the weight of the bag now. Let the new weight is W'.
So,
W' = 40 +36% of 40
i.e.
![W'=40+\dfrac{36}{100}\times 40\\W'=54.4\ pounds](https://tex.z-dn.net/?f=W%27%3D40%2B%5Cdfrac%7B36%7D%7B100%7D%5Ctimes%2040%5C%5CW%27%3D54.4%5C%20pounds)
So, the new weight of the bag is equal to 54.4 pounds.
![\bf \qquad \textit{Simple Interest Earned}\\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\to &\$6500\\ P=\textit{original amount deposited}\\ r=rate\to 2.6\%\to \frac{2.6}{100}\to &0.026\\ t=years\to &3 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%7D%5C%5C%5C%5C%0AI%20%3D%20Prt%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AI%3D%5Ctextit%7Binterest%20earned%7D%5Cto%20%26%5C%246500%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5C%5C%0Ar%3Drate%5Cto%202.6%5C%25%5Cto%20%5Cfrac%7B2.6%7D%7B100%7D%5Cto%20%260.026%5C%5C%0At%3Dyears%5Cto%20%263%0A%5Cend%7Bcases%7D)
she should have invested P, in order to get I = 6500
but she instead invested 17,801, how much more did she need? well, P - 17801
solve for P
Answer:
Depending on the length and width, it would be the length times the width.
Step-by-step explanation:
Answer:
z / 7
Step-by-step explanation:
C = O / H
O = z
H = 7