Answer: the probability that a truck drives between 166 and 177 miles in a day is 0.0187
Step-by-step explanation:
Since mileage of trucks per day is distributed normally, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = mileage of truck
µ = mean mileage
σ = standard deviation
From the information given,
µ = 100 miles per day
σ = 37 miles miles per day
The probability that a truck drives between 166 and 177 miles in a day is expressed as
P(166 ≤ x ≤ 177)
For x = 166
z = (166 - 100)/37 = 1.78
Looking at the normal distribution table, the probability corresponding to the z score is 0.9625
For x = 177
z = (177 - 100)/37 = 2.08
Looking at the normal distribution table, the probability corresponding to the z score is 0.9812
Therefore,
P(166 ≤ x ≤ 177) = 0.9812 - 0.9625 = 0.0187
His average speed is 12 and 2/3 km per hour
Step-by-step explanation:
1.
36
2×18
2×9
3×3 therefore prime factorization is 2²×3²
2.
42
2×21
3×7 therefore prime factorization is 2×3×7
3.
48
3×16
2×8
2×4
2×2 therefore prime factorization is 2⁴×3
4.
27
3×9
3×9 therefore prime factorization is 3³
Answer:
About 72%
Step-by-step explanation:
All you have to do is divide the number of children who traveled in third class (79) by the total number of children (109)
79/109=.724770642 OR 72%
2(a^2 - 5b) - (c^2 - 1) =
2a^2 - 10b - c^2 + 1 <===
