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Kazeer [188]
3 years ago
14

I need help with answer number 3. Help me please

Mathematics
1 answer:
posledela3 years ago
4 0
Do (6x12)/2, that should work
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Which of the following sets of sides does not form a right triangle?
kolezko [41]

Answer:

7, 24, 26

Step-by-step explanation:

6 squared is 36 and 8 squared is 64. Add them together and you get 100, which is 10 squared. Do the same for the other ones and you'll notice that 7 squared and 24 squared added together is 625, which is not 26 squared. In my head 25 squared is 625(check if you don't believe me) so I know that the answer is the third one. The basic formula for a right triangle is a^2 + b^2 = c^2, and that's how you find if three numbers form a right triangle or not. Hope this helps :)

3 0
3 years ago
A circle is centered O (0,0) and has the radius 3.46410161514 where does poing M (-3,2) lie​
larisa [96]

The circle area can be defined as x2 + y2 < 3.46^2.

For point M, x2 + y2 = 13.

Since 3.46^2 is about 12, point M is outside the circle!

6 0
3 years ago
Read 2 more answers
A pen costs $2.09 and a marker costs $1.45. Ken bought one pen and one marker
Reika [66]

Answer:

$1.46

Step-by-step explanation:

2.09 + 1.45 = 3.54

5 - 3.54 = 1.46

4 0
2 years ago
Which represents the solution(s) of the system of equations, y + 4 = x2 and y-x=2? Determine the solution set by
Sergeu [11.5K]

Answer:

The points (-2, 0) and (3,5) are the ONLY solutions of the given sets of equations.

Step-by-step explanation:

Here, the given equations are: y + 4 = x^{2}  , y -x = 2

Now checking for the given points:

(a) (-2, 0)

Here, y + 4 = 0 + 4 = 4 =   (-2)^{2}  =  x^{2} \\y- x = 0 -(-2) = 2  = RHS

Hence,  (-2, 0) is the solution of the given equations.

b) Checking for (2,0), as (-2, 0) is a solution as shown above

Here, y + 4 = 0 + 4 = 4 =   (2)^{2}  =  x^{2} \\y- x = 0 +  (-2) = -2  \neq 2(RHS)

Hence,  (2, 0) is NOT the solution of the given equations.

c) Checking for (3,5), as (-2, 0) is a solution as shown above

Here, y + 4 = 5 + 4 = 9 =   (3)^{2}  =  x^{2} \\y- x = 5 -3 = 2 -  (RHS)

Hence,   (3,5), is the solution of the given equations.

Hence, the points (-2, 0) and (3,5) are the ONLY solutions of the given sets of equations.

5 0
4 years ago
How to solve -5x(-7xcubed)
DerKrebs [107]

-5x(-7x^3)

Because -7x^3 is in parentheses, you add the degrees together:

35x^4

5 0
3 years ago
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