Let the weight of triangle be x units. You are given that the weight of square is 1 unit.
1) On the left side of the balanced beam you can see 3 triangles and 5 squares. The weight on left side is 3·x+5·1=3x+5 units.
2) On the right side of the balanced beam you can see 2 triangles and 7 squares. The weight on right side is 2·x+7·1=2x+7 units.
3) If the whole system is balanced, then the weights on left and right sides are equal:
3x+5=2x+7.
Solve this equation:
3x-2x=7-5,
x=2 units.
Answer: option A
Answer:
8
Step-by-step explanation:
-4-(-12)
If you take away a negative that means you are adding so you do -4+12 because there is a double negative.
Answer: j = -0.45
Step-by-step explanation:
2.25 – 11j – 7.75 +1.5j = 0.5j – 1
We can group similar terms:
-11j +1.5j -0.5j = -1 - 2.25 + 7.75
-10j = 4.5
j = 4.5/-10
j = -0.45
Answer: j = -0.45
<h2><em>Spymore</em></h2>
Answer:
Step-by-step explanation:
c.

250:1000
Divide both sides by 250
1:4