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Assoli18 [71]
3 years ago
10

Please answer ASAP! The number 650,000 written in scientific notation would be _____.

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Answer:

65x10^5

Step-by-step explanation:

Zanzabum3 years ago
3 0

Answer:

6.5 x 10^{5}

Step-by-step explanation:

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Solve for x 4x+ 14=6x-8
Tomtit [17]

x=11
x is equal to 11 because you subtract 4x from both sides and then add 8 to both sides where you are left with 2x=22. After dividing by 2, you get x=11
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3 years ago
What is (7z-5)-(3x-2) equivalent to ?
Tresset [83]

Answer:

7z -3x -3 is the solution to the equation

Step-by-step explanation:

7z -5 -3x +2

7z -3x -5+2

7z -3x -3

6 0
3 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
Solve<br><br> 4(3x - 2) = 52
guapka [62]

Answer:

x= 5

Step-by-step explanation:

first we open brackets

12x-8=52

then transpose

12x= 52+8

12x= 60

x= 60/12

x= 5

hope it helps , pls mark me as brainliest

5 0
3 years ago
Which section of the function is decreasing? (4 points)
vredina [299]

Answer:

Step-by-step explanation:

D

8 0
3 years ago
Read 2 more answers
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