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Bess [88]
4 years ago
10

A new moon would be directly overhead at what time

Advanced Placement (AP)
1 answer:
krek1111 [17]4 years ago
5 0

It is midnight when the moon sets. It is 6 p.m. when the moon rises in the east. It is 9 p.m. when the moon is half way up the sky between the eastern horizon and the highest point the moon can get looking south. It is midnight when the moon is at its highest point in the sky looking south.

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There are several views about what intelligence is. Briefly explain Charles Spearman's theory of general intelligence, Howard Ga
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Answer:

The answer is below

Explanation:

Charles Spearman's theory of General Intelligence often referred to as the "g" factor, explains a common mental proficiency that serves as the basis for the issue of several certain skills, such as verbal, spatial, numerical, and mechanical skills. Charles Spearman believes that general intelligence could serve as a predictor of all levels of distinct abilities.

Howard Gardner's theory of multiple intelligences on the other hand stated that humans possess various intelligence in which the Intelligence Quotient Test alone can not measure fully. The multiple intelligence humans possess are Linguistic, Logical-Mathematical, Spatial-Visual, Bodily-Kinesthetic, Musical, Interpersonal, Intrapersonal.

Robert Sternberg's theory of three intelligence stated that intelligent behavior is a byproduct of adequate proportion between analytical, creative, and practical abilities in humans and that these intelligent abilities work together to ensure that people acquire their objective within specific socio-cultural reality.

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Which school faculty member should you talk to about enrolling in an ap course??
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AP Calculus AB - Differentiating using the Product Rule
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Answer:

  h'(t) = (√t)(1 -5t²)/(2t)

Explanation:

First of all, your product rule needs to be written correctly.

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You have ...

h(t)=\sqrt{t}(1-t^2)\\\\f(t)=\sqrt{t} \qquad f'(t)=\dfrac{1}{2\sqrt{t}}=\dfrac{\sqrt{t}}{2t}\\\\g(t)=1-t^2 \qquad g'(t)=-2t\\\\h'(t)=f'(t)g(t)+f(t)g'(t)=\dfrac{\sqrt{t}}{2t}(1-t^2)+\sqrt{t}(-2t)\\\\h'(t)=\dfrac{\sqrt{t}(1-t^2-4t^2)}{2t}=\dfrac{\sqrt{t}(1-5t^2)}{2t}

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