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Alika [10]
4 years ago
8

Does anyone know this ?

Mathematics
2 answers:
Vinil7 [7]4 years ago
7 0

Answer:

its 100 square meters.

Step-by-step explanation:

(holy heck, I just got the exact question,)

idk how to explain, but basically , you do cut the shape into smaller shapes than do some math stuff called multiplication and bada bing dada boom, you get 100 square meters.

serious [3.7K]4 years ago
5 0

Answer:

100 centimeters

Step-by-step explanation:

Split the two figures and find each's area and then add it.

So the area of the triangle is 30 and the area of the rectangle is 70

70+30=100

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For ΔABC, ∠A = 3x - 8, ∠B = 5x - 6, and ∠C = 4x + 2. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' wit
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We all know that a triangle has 180 degrees.
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6 0
3 years ago
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How do u solve this question?
MrRa [10]

Answer:

a) 67 inches (y-intercept)

b) Vertex form y=(x+8)^2+3

c) Difference is 64 inches (vertex minus y intercept)

3 0
4 years ago
Match each quadratic equation with its roots. Tiles a2-a+11+0
laila [671]
To solve this problem you must aply the proccedure shown below:

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 b=-1
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7 0
4 years ago
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
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