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djyliett [7]
3 years ago
13

How do you use an exponent to represent a number such as 16

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
Hey there, well 4×4=16. Therefore, the exponent of 16 is 4²
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Total employment for sheet metal workers in 2016 is projected to be 201,000. If this is a 6.3% increase from 2006,
anastassius [24]

Answer:

<h2>A. <em><u>2</u></em><em><u>1</u></em><em><u>4</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em></h2>

Step-by-step explanation:

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3 0
3 years ago
Can someone help me please will give brainlist
nadya68 [22]

Answer:

A) it converges

B) 1998.047

C) 2000

d) The sum is getting smaller and smaller

Step-by-step explanation:

Formula: a_n+a_1*r^(r-1)

(1000*((0.5^10)-1))/(0.5-1)=1998.047

(1000*((0.5^30)-1))/(0.5-1)=2000

8 0
2 years ago
Dexter drove 546 miles on one tank of gasoline. His car’s gas tank holds 15 gallons of gas. Find the average number of miles he
AlexFokin [52]

546 mil / 15 gal = about 36.4 mil per gal

4 0
3 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
4 years ago
why do whole numbers raised to an exponent get greater while fractions raised to an exponent get smaller?
ehidna [41]
Any number above 1 gets greater, below 1 smaller (when above 0), while 1 itself remains the same. Negative numbers are more unpredictable.
8 0
3 years ago
Read 2 more answers
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