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3 years ago

Sorry it’s small I could not get it in just zoom in

Mathematics

1 answer:

Ne4ueva [31]3 years ago

3 0

Hello!

Graphs A and D are reflected, not rotated, so they are not the answer.

Graph C is rotated 180°, so it is not the answer.

This leaves us with B as our final answer.

I hope this helps!

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particals have enough energy to break free from eachother and can move around freely; particals spread out in different directio

Burka [1]

I cant find an answer for this sorry

4 0

3 years ago

Write in point-slope form the equation of the line that is parallel to the given line and passes through the given point.Your fi

SOVA2 [1]

Answer:

$y = x$

Step-by-step explanation:

The given equation is

$y = x + 5$

The slope of this line

$m = 1$

Since all parallel lines have the same slope, the slope of our line is also m=1.

We now use the point-slope formula

$y-y_1=m(x-x_1)$

Since the line passes through (-1,-1)

We gave

$x_1=-1,y_1=-1$

We substitute the slope and point to get

$y - - 1 = 1(x - - 1)$

$y + 1 = x + 1$

$y = x$

6 0

3 years ago

Find the measure of angle BCD in the following parallelogram. what's does BCD equal

DiKsa [7]

Answer:

120 degrees

Step-by-step explanation:

This is a quadrilateral, and by definition, the sum of all the interior angles is 360. So, we can just sum up all the expressions and set them equal to 360:

2x + x + 2x + x = 360

Combine like terms and solve for x:

6x = 360

x = 360/6 = 60

<BCD = 2x = 2 * 60 = 120

Thus, the answer is 120 degrees.

Hope this helps!

4 0

3 years ago

A data set has a mean of x = 71 and a standard deviation of 11.6. Find the z-score for each of the following.

olchik [2.2K]

Answer:

WHY MUST I CRYYYYY

Step-by-step explanation:

5 0

2 years ago

Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.

ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

$a_n = a_1 + d(n-1)$

Plug in $a_1 = 4, \ d = 8, \ n = 10$ and you should get the following:

$a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\$

The tenth term is <u>76</u>

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We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

$\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}$

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In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in $a_n = a_1 + d(n-1)$ which shifts everything one spot to the left.

7 0

2 years ago