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IgorC [24]
3 years ago
11

2. How many solutions does each equation

Mathematics
1 answer:
lakkis [162]3 years ago
7 0

Answer:

2 solution

answer is -c=0 or 0=c

10+3c-2=4c-c+8

3c-4c-c=8-10-2

-c=0

0=c

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Alchen [17]

Answer:

Length, l = 11 ft.

Width, w = 9 ft.

Step-by-step explanation:

From the given data, the area of the rectangle = 99 ft².

Area of the rectangle = Length, l X Width, w

Here, Length, l = 7 more than twice the width

⇒       Length, l = 7 + 2w

Therefore, Area, A = 99 = (7 + 2w)w

⇒ 99 = 7w + 2w²

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Solve the Quadratic equation using the formula: x = $ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $ for the quadratic equation ax² + bx + c = 0.

Therefore, w = $ \frac{-7 \pm \sqrt{7^2 -4(2)(-99)}}{2(2)} $

$ = \frac{-7 \pm \sqrt{49 + 8(99)}}{4} $

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Since, $ \sqrt{841} = 29 $ we get:

$ w = \frac{-7 \pm 29}{4} $

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We take the integer values.

If w = -9, then l = 2(-9) + 7

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Therefore, the length, l of the rectangle = - 11 ft.

and the width, w of the rectangle = - 9 ft.

Hence, the answer.

3 0
3 years ago
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